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pishuonlain [190]
3 years ago
11

PLEASE HELP FOR 15 BRAINY POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
evablogger [386]3 years ago
6 0

Answer:

i dont know sorry

Explanation:

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The Molar mass(M.w) in g/mol of 6.3 grams of an ideal gas that placed in 5.0 L tank at ST
BigorU [14]

Answer:

28 g/mol, N2

Explanation:

Given data:

Volume of gas = 5.0 L

Mass of gas = 6.3 g

Pressure = 1 atm

Temperature = 273 K

Molar mass of gas = ?

Solution:

We will calculate the density first.

d = mass/ volume

d = 6.3 g/ 5.0 L

d = 1.26 g/L

Molar mass:

d = PM/RT

M = dRT/P

M =  1.26 g/L× 0.0821 atm.L/mol.K × 273 K/ 1 atm

M = 28 g/mol

Molar mass of N₂ is 28 g/mol thus given gas is N₂.

7 0
3 years ago
According to Charles's law, under which conditions will the volume of a given amount of gas be proportional to temperature?
Pavel [41]
When the pressure is kept constant
5 0
3 years ago
Read 2 more answers
Identify the term that matches each definition.
Nikolay [14]

Answer:

a. Volatile.

b. Air foil.

c. Sash.

d. Work surface.

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Solid.

II. Liquid.

III. Gas.

Matching the terms with their respective definition, we have;

a. Volatile: A characteristic that describes substances that evaporate readily, producing large amounts of vapors.

b. Air foil: the front vent of a fume hood, which helps maintain proper air circulation.

c. Sash: the glass panel in front of the fume hood that shields the user from fumes and other hazards.

d. Work surface: the horizontal, flat area of a fume hood upon which experiments are carried out.

7 0
3 years ago
Whenever ___ energy is needed
vfiekz [6]
Well...........thanks for posting anyway. 
5 0
4 years ago
a sample of ammonia contains 9g hydrogen and 42g nitrogen. another sample contains 5g hydrogen .calculate the amount of nitrogen
balandron [24]
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen

9x=42 \cdot 5 \\
9x=210 \\
x \approx 23.33

The mass of nitrogen in the second sample is 23.33 g.
4 0
4 years ago
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