2SO2(g)+O2(g)→2 SO3(g), here reaction entropy decreases as the number of gas moles decreases from reactions to products.
HCL(g)+NH3(g)→NH4CL(s), entropy decreases as molecules of gas are converted into solid.
CO2(s)→CO2(g), entropy increases as gas is formed from a solid.
Cao(s)+CO2(g)→Caco3(s), entropy increases as gas is converted into a solid.
Answer:
THE NEW VOLUME OF THE OXYGEN GAS AT 28 PSI FROM 72.5 PSI IS 0.078 L.
Explanation:
Initial volume of the oxygen in the container = 30.0 mL = 30 / 000 L = 0.03 L
Initial pressure of the oxygen = 72.5 psi = 1 psi = 6890 pascal
Final pressure = 28 psi
Final volume = unknown
First convert the mL to L and since both pressures are in similar unit that is psi; there is no need converting them to pascal or other standard unit of pressure. They cancel each other out.
This question follows Boyle's equation of gas laws and mathematically it is written as:
P1 V1 = P2 V2
Re-arranging by making P2 the subject of the formula, we have:
V2 = P1 V1 / P2
V2 = 72,5 * 0.03 / 28
V2 = 2.175 /28
V2 = 0.0776 L
The new volume of the oxygen gas at a change in pressure from 72.5 psi to 28 psi is 0.078 L.
* Answer: 448.056 meters *
——
1 yard = .9144 meters (according to Google)
100 yards= 91.44 meters
——
100*4.9= 490 yards
490 yards = 448.056 meters
* 4.9 Football fields= 448.056 meters *
I hope this helps! :)
Answer:
i think its b.c but I'm not sure
Answer:
1. The gas law used: Dalton's law of partial pressure.
2. Pressure of nitrogen = 331 mmHg
Explanation:
From the question given above, the following data were obtained:
Total pressure (Pₜ) = 592 mmHg
Pressure of Oxygen (Pₒ) = 261 mmHg
Pressure of nitrogen (Pₙ) =?
The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:
Pₜ = Pₒ + Pₙ
592 = 261 + Pₙ
Collect like terms
592 – 261 = Pₙ
331 = Pₙ
Pₙ = 331 mmHg
Therefore, the pressure of nitrogen in the sample is 331 mmHg
