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umka21 [38]
3 years ago
6

Where else do you see Force & Motion in real-world experiences?

Chemistry
2 answers:
qwelly [4]3 years ago
7 0

Answer:

<h2>Daily traffic. </h2><h2>Amusement parks.</h2><h2>Gymnastic.</h2>

Explanation:

Force and Motion are everywhere like daily traffic, amusement parks and gymnastic. This to physical magnitudes are everywhere because all objects are relatively moving, and to do that a force is needed to being applied, because force means to give acceleration to a body, which can cause movement, in case it doesn't, it's said that the system is in equilibrium.

Paladinen [302]3 years ago
4 0

Answer:

a boy pulling a toy train, the boy is

interacting with an object while applying a force to it,

another example of contact forces is friction.

Explanation:

A contact force is when two interacting  

objects

(btw love your pfp)

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What quantity of heat is transferred when a 150.0g block of iron metal is heated from 25.0°C to 73.3°C? What is the direction of
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The direction of heat flow is increased which means blocks temperature is higher and hotter than it was before

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What is the definition of a Lewis acid?
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A Lewis acid is a chemical species that contains an empty orbital which is capable of accepting an electron pair from a Lewis base to form a Lewis adduct

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3 years ago
. the density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v). densit
ale4655 [162]

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

<h3>What is Density ?</h3>

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = \frac{\text{Mass}}{\text{Volume}}  or d = \frac{m}{V}

<h3>What is Intensive Property ? </h3>

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.  

<h3>What is Extensive property ?</h3>

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Learn more about Density here: brainly.com/question/1354972

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = \frac{\text{Mass}}{\text{Volume}}  or d = \frac{m}{V}

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

5 0
2 years ago
The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
Brrunno [24]

Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = \left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}

n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Molecular formula = 4 \times C_{2}H_{4}O

Molecular formula is C_{8}H_{16}O_{4}

6 0
3 years ago
A solution is made by dissolving 10.7 g of magnesium sulfate, MgSO4, in enough water to make exactly 100 mL of solution. Calcula
adell [148]

Answer:

[MgSO₄] = 890 mM/L

Explanation:

In order to determine molarity we need to determine the moles of solute that are in 1L of solution.

Solute: MgSO₄ (10.7 g)

Solvent: water

Solution: 100 mL as volume. (100 mL . 1L / 1000mL) = 0.1L

We convert the solute's mass  to moles → 10.7 g / 120.36 g/mol = 0.089 moles

Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M

In order to calculate M to mM/L, we make this conversion:

0.89 mol . 1000 mmoles/ 1 mol = 890 mmoles

4 0
3 years ago
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