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torisob [31]
2 years ago
6

Función que describe el movimiento armónico simple

Chemistry
1 answer:
n200080 [17]2 years ago
3 0
Sorry I don’t understand
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ZnSO4 +<br> +<br> LINO, → ---- Zn(NO3)2<br> +<br> Li,SO4<br> Balanced equation
Tanzania [10]

Answer:

ZnSO4 + 2LiNO3 → Zn(NO3)2 + Li2SO4

Explanation:

There's many resources on web that can assist you with this concept:

https://en.intl.chemicalaid.com/tools/equationbalancer.php

https://www.webqc.org/balance.php

4 0
3 years ago
How many electrons each atom gives or takes in KBr
notsponge [240]
K gives 1 electron, and Br takes 1 electron.
4 0
3 years ago
Aspartame (c14h18n2o5) is a solid used as an artificial sweetener. its combustion produces carbon dioxide gas, liquid water, and
Law Incorporation [45]

Aspartame (C₁₄H₁₈N₂O₅) is a solid used as an artificial sweetener. its combustion produces carbon dioxide gas, liquid water, and nitrogen gas

C₁₄H₁₈N₂O₅ + 16O₂-----> 14CO₂ + 9H₂O + N₂.

As it can be seen from the equation, that the coefficient of nitrogen gas in the balanced equation for the reaction is 1.

So the answer here is 1 only that is coefficient of nitrogen gas in the balanced equation for the reaction is 1.

5 0
3 years ago
What is the molality of a solution if 100.0 g of glucose (C&amp;Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2
Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)

the enthalpy of reaction is given as  ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ

7 0
3 years ago
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