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Reika [66]
3 years ago
15

9.03g of magnesium combine completely with 4.30g of nitrogen

Chemistry
1 answer:
Readme [11.4K]3 years ago
5 0

it is 12.51 grams cause u just add them together

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HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?
Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0
3 years ago
#1: What is the charge on an electrically neutral atom of hydrogen?
MakcuM [25]
<span>my answer is B.The electrical charge of the hydrogen atom is thought to be exactly zero. This is a consequence of the apparent equality of the magnitude of the electrical charges of the electron and the proton, and their opposite sign. The electrical charge of neutral atoms has been measured to be zero, with an uncertainty of something like 10^(-20) e, where e is the elementary charge.</span>
5 0
4 years ago
Read 2 more answers
When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be
Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

        AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

                    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                     0.269 M = \frac{\text{no. of moles}}{1.14 L}

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                   0.307 mol = \frac{mass}{143.32 g/mol}

                           mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

                 

8 0
3 years ago
If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?
lianna [129]

Answer:

5.22*1022 molecules of glucose (C6H12O6)  is equal to 15.08 grams

Explanation:

Number of molecule of glucose in one mole = 6.023 * 10^{23}

Now mass of one mole of glucose = 180 grams

Number of moles in 6.023 * 10^{23} molecules of glucose = 1

Number of moles in 1 molecules of glucose =  \frac{1}{6.023 * 10^{23}}

Number of moles in 5.22 * 10^{22} molecules of glucose =  \frac{5.22* 10^{22}}{6.023 * 10^{23}}  = 0.083 moles

Weight of 0.083 moles

= 0.083 * 180\\= 15.08grams

7 0
3 years ago
What is the median of the following set: 2, 4, 6, 8, and 10?
labwork [276]

Answer:9

Explanation:

(3+8+10+15)/4 = 36/4 = 9

6 0
3 years ago
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