A pendulum starts out at its highest point with 10 Joules of Potential Energy. When it reaches the lowest point of its swing, ho
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Answer:
337.22 K
Explanation:
Given that:
P₁ = 1 atm
T₁ = 350 K
P₂ = 0.639 atm
T₂ = ??? (unknown)
R(rate constant) = 8.34 J k⁻¹ mol⁻¹
Using Clausius-Clapeyron equation, we can determine the final boiling point of the process.
Clausius-Clapeyron equation can be written as:
Substituting our values given; we have:
∴ the boiling point of CH3COOC2H5 when the external pressure is 0.639 atm is <u>337.22</u> K.