M₁=50 g
m₀=60 g
w=100m₁/m₀
w=100*50/60=83.3%
Answer:
8.0 mol O₂
Explanation:
Let's consider the complete combustion reaction of C₉H₁₂.
C₉H₁₂ + 12 O₂ → 9 CO₂ + 6 H₂O
The molar ratio of C₉H₁₂ to O₂ is 1:12. The moles of O₂ required to react with 0.67 moles of C₉H₁₂ are:
0.67 mol C₉H₁₂ × (12 mol O₂/1 mol C₉H₁₂) = 8.0 mol O₂
8.0 moles of O₂ are required to completely react with 0.67 moles of C₉H₁₂.
B) brings order to the elements. This is correct because elements are in order by highest atomic number.
