3 years ago

Can Anyone help me with this?

Physics

2 answers:

zepelin [54]3 years ago

8 0

1. velocity

2. direction

3 idk

4 idk

5 . d

agasfer [191]3 years ago

7 0

1. Velocity

2. Time

3. Idk

4. Idk

5. D. I think it may be A. but I think D.

You might be interested in

the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ

stiks02 [169]

Answer:

D. Increases from pole to equator

Explanation:

I majored in Science

8 0

3 years ago

I need help on 6, 7, 8, and 9

Ivahew [28]

6 is b. part B on 6 is a. 7 is a. partB ON 7 b

5 0

3 years ago

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v0 = 15.0 m/s. The cliff i

ankoles [38]

Answer:

(a) x0 = 0m and y0 = 49.0m

(b) Vox = 15.0m/s Voy = 0m/s

(d) X = 15.0t and y = 49.0 - 4.9t²

(e) t = 3.16s

(f) Vf = 34.4m/s

Explanation:

8 0

3 years ago

Imagine a place in the cosmos far from all gravitational and frictional influences. Suppose that you visit that place (just supp

xz_007 [3.2K]

The rock will continue to travel in a straight line with a constant velocity for ever... The reason is, once it leaves your hand there is no force acting on the rock, so it will just continue to move in a natural motion which is constant velocity.

6 0

3 years ago

A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude

earnstyle [38]

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

$p=(10.0 kg)(12.0 m/s)=120 kg m/s$

4 0

3 years ago