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Simora [160]
3 years ago
10

Which of the following statements describe the transfer of energy?

Physics
1 answer:
Lady_Fox [76]3 years ago
7 0

The answer should be A weighlifter lifting 100lb. bell bar from his chest to a certain height.

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What is the time it takes a pig to roll a distance of 6 m at a speed of 8 m/s? 0.7 m/s
Rudik [331]

Answer:

0.75 s

Explanation:

From the basic definition of sleed as distance traveled per unit time, s=d/t and making t the subject of the formula then t=d/s where t is time of traveling, d is distance covered and s is the speed. Substituting 6m for distance, d and 8 m/s for speed s then the time is calculated as t=6/8=0.75 s

Therefore, time is equivalent to 0.75 s

3 0
3 years ago
As steam is slowly injected into a turbine, the angular acceleration of the rotor is observed to increase linearly with the time
gavmur [86]

Answer:

217.04 rad/s

Explanation:

We are given that

Initial velocity,\omega_0=0

t=10 s

Number of rev=20

We have to find the angular velocity at t=24 s

\theta_1=2\pi\times 20=40\pi rad

\alpha=kt

\frac{d\omega}{dt}=kt

\int d\omega=\int_{0}^{t} ktdt

\omega=\frac{kt^2}{2}

\frac{d\theta}{dt}=\frac{kt^2}{2}

\int d\theta=\int_{0}^{t}\frac{kt^2}{2} dt

\theta=\frac{kt^3}{6}

Substitute the values

40\pi=\frac{k(10)^3}{6}

k=\frac{40\pi\times 6}{(10)^3}=\frac{24\pi}{100}

Substitute the value of k and t=24

\omega=\frac{24\pi\times (24)^2}{2\times 100}=217.04 rad/s

8 0
4 years ago
While doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm. The accepted value for the density o
Yuri [45]
<span>5.56%. The formula for percent error is: Percent Error = (|Theoretical value - Experimental value| / Theoretical value) x 100. Remember that the percent error is unitless, and to keep significant figures even after calculations.</span>
8 0
3 years ago
. A radio station transmitting at a frequency of 200KH, emits waves of wavelength 1.5 km.the velocity of the radio waves is​
Karolina [17]

Answer:

Explanation: as,

v=f∧

v=200×10³×1.5×10³

v=2.7×10^7ms⁻¹

4 0
3 years ago
A 500 lb steel beam is lifted up by a crane to a height of 100 ft and is held there.
Nadya [2.5K]

A. How much work is being done to hold the beam in place?

Work is the product of Force and Displacement. Since there is no Displacement involved in just holding the beam in place, hence the work is zero.

 

B. How much work was done to lift the beam?

In this case, force is simply equal to weight or mass times gravity. Hence the work is:

Work = weight * displacement

Work = 500 lbf * 100 ft

Work = 50,000 lbf * ft

 

C. How much work would it take if the steel beam were raised from 100 ft to 200ft?

The displacement is still 100 ft since 200 – 100 = 100 ft, hence the work done is still similar in B which is:

<span>Work = 50,000 lbf * ft</span>

5 0
3 years ago
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