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2 years ago

Check my work please

1 answer:

6 0

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 273 x 340 / 713

P2 = 130 kPa

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The length of a vector indicates the magnitude of the vector. true or false

WITCHER [35]

Answer:

True

Explanation:

4 0

2 years ago

Read 2 more answers

Com que rapidez estará sendo feito trabalho elétrico num resistor de 10 ohms, percorrido por uma corrente elétrica de 5 A? Qual

34kurt

Poder = (resistencia) x (corrente)²

Poder = (10 ohms) x (5 A)²

Poder = 250 watts (250 Joule por segundo)

2 horas = 7,200 segundos

Energia = (250 joule/seg) x (7,200 seg)

Energia = 1,800,000 Joules

7 0

2 years ago

Monochromatic light of wavelength λ=136.8μ m is shone at normal incidence through a thin film of thickness t resting atop a full

inn [45]

Answer:

1.8 × 10⁻⁸ Hm

Explanation:

Given that:

The refractive index of the film = 19

The wavelength of the light = 136.8 μ m

The thickness can be calculated by using the formula shown below as:

$Thickness=\frac {\lambda}{4\times n}$

Where, n is the refractive index of the film

${\lambda}$ is the wavelength

So, thickness is:

$Thickness=\frac {136.8\ \mu\ m}{4\times 19}$

Thickness = 1.8 μ m

Since,

1 μ m = 10⁻⁸ Hm

So,

Thickness = 1.8 × 10⁻⁸ Hm

7 0

2 years ago

Two masses (5.3kg and 7.5kg) are fastened together with a small amount of explosive. They are loaded into a spring gun that is t

Vsevolod [243]

Answer:

8.2

Explanation:

8 0

2 years ago

The AC voltage source is connected to an inductor and a resistor in series. If the frequency of the source is increased the curr

DaniilM [7]

Answer:

If the frequency of the source is increased the current in the circuit will decrease.

Explanation:

The current through the circuit is given as;

$I = \frac{V}{Z}$

Where;

V is the voltage in the AC circuit

Z is the impedance

$Z = \sqrt{R^2 + X_L^2}$

Where;

R is the resistance

$X_L$ is the inductive reactance

$X_L$ = ωL = 2πfL

where;

L is the inductance

f is the frequency of the source

Finally, the current in the circuit is given as;

$I = \frac{V}{\sqrt{R^2 + (2\pi fL)^2} }$

From the equation above, an increase in frequency (f) will cause a decrease in current (I).

Therefore, If the frequency of the source is increased the current in the circuit will decrease.

5 0

2 years ago