Answer:
A = 4.76 x 10⁻⁴ m²
Explanation:
given,
weight of the person = 625 N
weight of the bike = 98 N
Pressure on each Tyre = 7.60 x 10⁵ Pa
Area of contact on each Tyre = ?
total weight of the system = 625 + 98
= 723 N
Let F be the force on both the Tyre
F + F = W
2 F = 723
F = 361.5 N
F = P A
A = 4.76 x 10⁻⁴ m²
Gamma rays will damage - I mean almost instantly kill you. Gamma rays were the reason for one of Earth's biggest mass destinction
Answer:
57.4 m/s
Explanation:
Component of vectors parallel to the ground = v sin(titha)
= 100×sin35
= 57.4 m/s
You can read further:
https://www.mathalino.com/reviewer/engineering-mechanics/components-of-a-force
In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes
. Solving the equation where d=8 and a=9.8 makes the time
=1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.
Here are two ways to do it:
<u>Way #1:</u>
-- You know that gravity accelerates things that are falling freely, adding 9.8 m/s to their speed every second.
-- After 6 seconds, an object that fell from rest winds up falling at (9.8 x 6) = 58.8m/s.
-- During that time, its average speed was 1/2(0 + 58.8) = 29.4 m/s .
-- In 6 seconds, at an average speed of 29.4 m/s, it covers (29.4 x 6) = <em>176.4meters</em>.
<u>Way #2:</u>
This way only works if you remember the formula for the distance covered during uniform acceleration.
D = 1/2 (acceleration) (time)²
Acceleration = gravity = 9.8 m/s²
Time = 6 seconds
D = 1/2 (9.8) (6)² = <em>176.4 meters</em>.