Answer:
If i am correct It should be 1/4 of an inch
Explanation:
Sorry but i can't quite explain
Answer:
(a) ------(3). (b)------(1) (c)-----(5) (d)------(2) ------ (e) -----4
Note: Kindly find an attached copy of the diagram associated with the solution to the question below.
Sources: the diagram to this question was researched from Quizlet
Explanation:
Solution
(1) Part (a)a waveform has a high frequency components compared to another waveform. the corresponding frequency components should be high.
So for the wave form a the corresponding frequency spectrum is (3)
(2) For part (b), waveform has three harmonics, the corresponding frequency spectrum is (1)
(3) The time domain waveform plot (c) is a sine wave but there exists a dc component.
Thus x[0] ≠0
For (c) the corresponding frequency spectrum is (5)
(4) For part (d) the corresponding frequency spectrum is (2)
(5) A sine wave is made of a single frequency only and its spectrum is a single point
For (e) the corresponding frequency spectrum is (4)
Answer:
1964
Explanation:
It was discovered in 1964 when a pair of Geiger counters were carried on board a sub-orbital rocket launched from New Mexico.
Answer:
(4.5125 * 10^-3 kg.m^2)ω_A^2
Explanation:
solution:
Moments of inertia:
I = mk^2
Gear A: I_A = (1)(0.030 m)^2 = 0.9*10^-3 kg.m^2
Gear B: I_B = (4)(0.075 m)^2 = 22.5*10^-3 kg.m^2
Gear C: I_C = (9)(0.100 m)^2 = 90*10^-3 kg.m^2
Let r_A be the radius of gear A, r_1 the outer radius of gear B, r_2 the inner radius of gear B, and r_C the radius of gear C.
r_A=50 mm
r_1 =100 mm
r_2 =50 mm
r_C=150 mm
At the contact point between gears A and B,
r_1*ω_b = r_A*ω_A
ω_b = r_A/r_1*ω_A
= 0.5ω_A
At the contact point between gear B and C.
At the contact point between gears A and B,
r_C*ω_C = r_2*ω_B
ω_C = r_2/r_C*ω_B
= 0.1667ω_A
kinetic energy T = 1/2*I_A*ω_A^2+1/2*I_B*ω_B^2+1/2*I_C*ω_C^2
=(4.5125 * 10^-3 kg.m^2)ω_A^2
Answer:
Student A
Explanation:
hope this helps have a great day