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3 years ago

An HVAC contracting company sent out three work crews to complete three

Engineering

1 answer:

Doss [256]3 years ago

6 0

Answer: 156 hours

Explanation:

Crew One worked 10-, 9-, 11-, 12-, and 9-hours for the week. The total hours worked by Crew One will be:

= 10 + 9 + 11 + 12 + 9

= 51 hours.

Crew Two worked 9, 12, 12, 9 and 9 hours. The total hours worked by Crew Two for the week will be:

= 9 + 12 + 12 + 9 + 9

= 51 hours

Crew Three worked 12-, 12-, 10-, 9-, and 11-hour daily. The total hours worked by Crew Three for the week will be:

= 12 + 12 + 10 + 9 + 11

= 54 hours

The total hours worked by the three crews for the week will be:

= 51 hours + 51 hours + 54 hours

= 156 hours

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What is the IMA of this pulley belt system if the diameter of the input

Stella [2.4K]

Answer:

2.8

Explanation:

The ideal mechanical advantage of the pulley IMA = D'/D where D' = diameter of output pulley = 7 inches and D = diameter of input pulley = 2.5 inches

So, IMA = D'/D

= 7/2.5

= 2.8

So, the ideal mechanical advantage of the pulley IMA = 2.8

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3 years ago

SMAW and GMAW use constant current arc welding machines.<br><br> True<br><br> False

Oksi-84 [34.3K]

It is true. Good luck

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3 years ago

Two containers initially contain dry air at 40 °C. Water is added to both containers so that the relative humidity is 30% in con

enot [183]

Answer:

A) Wet bulb temperature of #1 is less than that of #2

Explanation:

This can be gotten from pinpointing the states of the two containers on a psychometric chart.

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3 years ago

The mass fraction of eutectoid cementite in a hypoeutectoid iron-carbon alloy (just below its eutectoid temperature) is 0.109. O

Zinaida [17]

Answer:

The composition of an alloy is 0.75%wt

Explanation:

Let alloy is a hypoeutectoid alloy.

So, we can apply lever rule which is shown below.

$W_{a}=$ $\frac{C_{0} -C_{a} }{C_{b}-C_{a} }$

We know that $C_{a}=0.022$ and $C_{b}=6.7$

Given that $W_{a}=0.109$ , we have to find $C_{0}$

Thus,

$0.109=\frac{C_{0}-0.022 }{6.7-0.022}$

Hence

$C_{0}=0.75$ %wt

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3 years ago

calculate how much black eyes seeds are necessary to plant a 6- hectare( 14.425 acres) field. given that the weight of 1000 blac

11111nata11111 [884]

Answer: 1.38g

Explanation:

Width of planting area = 100m

Field size = 6-hectares(14.425 acres)

Weight of 1000 black eye seed = 230g

1 lb = 453.4g

1 black eye seed = 230g/1000 = 0.23g = 0.00023kg

1 hectare = 10,000sq metre

6 hectare = 60,000sq metre

(Weight/Area) kg/m2

0.00023kg / 10,000 = 2.3×10^-8kg/m^2

And field size = 6hectares = 60,000m^2

(2.3×10^-8) × 60,000 = 0.00138kg of black eye seed

0.00138kg × 1000 = 1.38g

6 0

3 years ago