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Advocard [28]
3 years ago
12

Example – a 100 kW, 60 Hz, 1175 rpm motor is coupled to a flywheel through a gearbox • the kinetic energy of the revolving compo

nents is 300 kJ at rated speed – the motor is plugged to a stop and allowed to run up to 1175 rpm in the reverse direction • calculate the energy dissipated in the rotor
Engineering
1 answer:
rjkz [21]3 years ago
7 0

Answer:

1200KJ

Explanation:

The heat dissipated in the rotor while coming down from its running speed to zero, is equal to three times its running kinetic energy.

P (rotor-loss) = 3 x K.E

P = 3 x 300 = 900 KJ

After coming to zero, the motor again goes back to running speed of 1175 rpm but in opposite direction. The KE in this case would be;

KE = 300 KJ

Since it is in opposite direction, it will also add up to rotor loss

P ( rotor loss ) = 900 + 300 = 1200 KJ

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Vehicles begin arriving at an amusement park 1 hour before the park opens, at a rale of four vehicles per minute. The gale to th
Alina [70]

Answer:

a) ≈ 30 mins

b) 8 vpm

Explanation:

<u>a) Determine how long after the first vehicle arrival will the queue dissipate</u>

The time after the arrival of the first vehicle for the queue to dissipate

= 29.9 mins ≈ 30 mins

<u>b) Determine the average service rate at the parking lot gate </u>

U = A / t

where : A = 240 vehicles , t = 30

U = 240 / 30 = 8 Vpm

attached below is a detailed solution of the given problems above

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3 years ago
I’m bored let’s text
Nuetrik [128]

Answer:

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3 years ago
Read 2 more answers
The explosion of a hydrogen bomb can be approximated by a fireball with a temperature of 7200 K, according to a report published
Iteru [2.4K]

Answer:

a

The rate of radiation of the energy is  E_r = 1.523747635*10^9 W/m^2

b

The irradiation is  G =46.177\ kW/m^2

c

The amount of energy absorbed is E_B = 461.772 KJ

d

The oak Tree would catch fire because the temperature of the blast(7200 K) is higher than the flammability limit (650 K) of the oak tree and secondly the thickness is very small

Explanation:

  From the question we are told that

        The  temperature is  T =  7200K

        The diameter of the ball is  d = 1.5 km = 1.5 *1000 = 1500m

       Hence the radius  == \frac{1500}{2} = 750m

 The total energy radiated can be mathematically represented as

                         E = \sigma A T^4

Where \sigma is the Stefan-Boltzmann constant \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 5.67*10^{-8} W \ \cdot m^{-2} K^{-4}

            A is the area of a sphere  = \pi d^2  = 3.142 * 1500^2 = 7.069500 *10 ^6\ m^2

 Substituting values we have

                    E = 5,67*10^{-8} * 7.069500*10^6 * 7200^4

                        =1.077*10^{15} W

Now the state of the energy is mathematically represented as

                           Rate  \ of \ energy \ radiation (E_r)= \frac{E}{A} = \sigma T^4

                                                            = 5.67*10^{-8} * 7200^2

                                                            = 1.523747635*10^9 W/m^2

A sketch illustrating the b part of the question is shown on the first uploaded image

     looking at the height at which the blast occurs(16km) as compared to the height of the wall we notice that the height of the wall is negligibly small

      from the diagram x can be calculated as follows

                      x = \sqrt{40^2 + 16^2}

                        = 43.0813 Km

This value of x represents the radius of the blast(assuming it is spherical ) when it is at that wall

Now the irradiation G is mathematically represented as

                              G = \frac{E}{4 \pi r^2}

Here r = 43.0813 Km = 43.0813 × 1000 = 43081.3 m

                            G= \frac{1.077*10^15}{4 \pi (431081.3^2)}

                                G =46.177\ kW/m^2

Generally the amount of energy absorbed can be mathematically represented as

                            Amount \ of \ energy \ absorbed \ (E_B ) = G * t

Where t is the time taken

       Therefore     E_B = 46.177 *10 = 461.77 KJ

       

                         

                       

             

   

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Aleksandr-060686 [28]

Answer:

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