Example – a 100 kW, 60 Hz, 1175 rpm motor is coupled to a flywheel through a gearbox • the kinetic energy of the revolving compo nents is 300 kJ at rated speed – the motor is plugged to a stop and allowed to run up to 1175 rpm in the reverse direction • calculate the energy dissipated in the rotor
1 answer:
Answer:
1200KJ
Explanation:
The heat dissipated in the rotor while coming down from its running speed to zero, is equal to three times its running kinetic energy.
P (rotor-loss) = 3 x K.E
P = 3 x 300 = 900 KJ
After coming to zero, the motor again goes back to running speed of 1175 rpm but in opposite direction. The KE in this case would be;
KE = 300 KJ
Since it is in opposite direction, it will also add up to rotor loss
P ( rotor loss ) = 900 + 300 = 1200 KJ
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Answer:
ananswer my question please
Answer:
461 C
862 F
Explanation:
The specific gas constant for CO2 is
R = 189 J/(kg*K)
Using the gas state equation:
p * v = R * T
T = p * v / R
v = 1/δ
T = p / (R * δ)
T = 9.3*10^6 / (189 * 67) = 734 K
734 - 273 = 461 C
461 C = 862 F
Turbooooooooooi Hope it helps Mister
The answer is the third option, piston I hope I helped ! ((:
Answer:
A) Q + W = n1 Cp ( T3 - T1 ) + n2Cp ( T2 - T1 )
Explanation:
A) The equation that would use to find Q
Q + W = n1 Cp ( T3 - T1 ) + n2Cp ( T2 - T1 )
Attached below is the remaining part of solution