A wildlife shelter is home to birds, mammals, and reptiles. If cat chow is sold in 30 lb bags, what is the least number of bags of cat chow needed for one year at this shelter? Will give brainliest if I see it
2 answers:
Answer:
26 bags
Step-by-step explanation:
A bag of cat chows = 30 lbs
Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow
There are at least 52 weeks in a year.
The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow
= 52 × ½
= 52/2
= 26 bags of cat chow
At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.
Answer:
13, the reasoning is....
15 (the amount of food per week) times 52 (the amount of months in a year) is 780. Divided 780 by 60 (the amount of pounds of food per bag) and you get 13. Have fun with your answer and good luck :D
You might be interested in
Answer:
A
Step-by-step explanation:
it goes down by 9 and left by 3
Answer:
59
Step-by-step explanation:
b^3 is 27
2(27) is 54
54+5 is 59
if u mean (2b)^3 then 2b is 6
6^3 is 216
plus 5 is 221
Answer:
I'm guessing C
Step-by-step explanation:
I don't think this is the correct way to answer it. But I litterly rotated it in my brain and got 7.5....
Answer:
50
Step-by-step explanation:
Answer:
intervals (-3,-1) and (0,+infinity)
Step-by-step explanation:
if f'(x)>0 then f is increasing