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Rufina [12.5K]
3 years ago
6

A wildlife shelter is home to birds, mammals, and reptiles. If cat chow is sold in 30 lb bags, what is the least number of bags

of cat chow needed for one year at this shelter? Will give brainliest if I see it

Mathematics
2 answers:
kotykmax [81]3 years ago
4 0

Answer:

26 bags

Step-by-step explanation:

A bag of cat chows = 30 lbs

Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow

There are at least 52 weeks in a year.

The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow

= 52 × ½

= 52/2

= 26 bags of cat chow

At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.

Bad White [126]3 years ago
3 0

Answer:

13, the reasoning is....

15 (the amount of food per week) times 52 (the amount of months in a year) is 780. Divided 780 by 60 (the amount of pounds of food per bag) and you get 13. Have fun with your answer and good luck :D

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Answer:

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The  mAngleVSR   m Angle VSR  is  mathematically given as

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This is further explained below.

<h3>What is mAngleVSR?</h3>

Generally, Draw two lines: one that connects the points R, S, and U, and another that connects the points V, S, and T. (see attached diagram). At point S, these lines come together to create four angles, which are denoted by the letters RSV, VSU, UST, and TSR respectively.

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