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Rufina [12.5K]
2 years ago
6

A wildlife shelter is home to birds, mammals, and reptiles. If cat chow is sold in 30 lb bags, what is the least number of bags

of cat chow needed for one year at this shelter? Will give brainliest if I see it

Mathematics
2 answers:
kotykmax [81]2 years ago
4 0

Answer:

26 bags

Step-by-step explanation:

A bag of cat chows = 30 lbs

Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow

There are at least 52 weeks in a year.

The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow

= 52 × ½

= 52/2

= 26 bags of cat chow

At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.

Bad White [126]2 years ago
3 0

Answer:

13, the reasoning is....

15 (the amount of food per week) times 52 (the amount of months in a year) is 780. Divided 780 by 60 (the amount of pounds of food per bag) and you get 13. Have fun with your answer and good luck :D

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Perimeter of a square painting is 216 centimeters. How long is each side?
RUDIKE [14]
Perimeter is the addition of all 4 sides and a square as all the same sides. so every side will be the same. so if you divide 216 by 4 you get 54. you can check this by adding 54+54+54+54=216 or 54x4=216
8 0
2 years ago
Which of the following represents x =1/3y written in general form?
Serhud [2]

If you would like to write x = 1/3 * y in general form, you can do this using the following steps:

The general form of the equation is: ax + by + c = 0.

x = 1/3 * y

x - 1/3 * y = 0


The correct result would be x - 1/3 * y = 0.

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3 years ago
How much confetti is dropped at the super bowl?
slamgirl [31]
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6 0
3 years ago
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
Suppose f(x) =x^2 and g (x) = 2x -3 what is the value of g (4)+f(-3)
Alona [7]

Answer:

d

Step-by-step explanation:

u just have to plug in the numbers

f(-3)= -3^2

f(-3)= 9

g(4)=2(4)-3

g(4)=5

9+5=14

I hope I'm right and hope I helped:)

6 0
3 years ago
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