Ans(a):
Given function is 
we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0
so let's solve
x+4≠0 for x
x≠0-4
x≠-4
Hence at x=4, function can't have solution.
Ans(b):
We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)
so we get:
g(x)=f(x)+4
We may simplify this equation but that is not compulsory.
Comparision:
Graph of g(x) will be just 4 unit upward than graph of f(x).
Ans(e):
To find value of x when g(x)=8, just plug g(x)=8 in previous equation
4x-3x=-1-16
x=-17
Hence final answer is x=-17
Answer: 113.04
Step-by-step explanation: The equation for the area of a circle is pi r squared so you have to find the radius first. To find the radius, find the diameter first. A way to do this which was easiest for me was dividing 37.68 by pi (3.14), which is 12. Divide the diameter by 2 to find the radius, 6.
Now use the equation from the beginning, pi r squared. So plug in pi as 3.14, then the radius as 6. It is important to always square the radius first, which would be 36. Now multiply 36 by 3.14, and there should be your answer.
When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
The sum(9) of half of the first number(1/2a) and one third of the second number(+1/3b)
That is correct
