It'll be my pleasure to analyze the circuit, describe my analysis in detail,
and give you a clear, precise, and accurate answer.
As soon as you let me see the circuit diagram, with values marked on
all of its components and power sources.
The absolute pressure is given by the equation,
![P_{abs}=P_{atm}-P_{vac}](https://tex.z-dn.net/?f=P_%7Babs%7D%3DP_%7Batm%7D-P_%7Bvac%7D)
Here,
is absolute pressure,
is atmospheric pressure and
is vacuum pressure.
Therefore,
![P_{abs}=98 kPa-80 kPa=18kPa](https://tex.z-dn.net/?f=P_%7Babs%7D%3D98%20kPa-80%20kPa%3D18kPa)
The gage pressure is given by the equation,
.
Thus,
.
In kn/m^2,
The absolute pressure,
![P_{abs}=18kPa(\frac{1kN/m^2}{kPa}) =18\ kN/m^2](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18kPa%28%5Cfrac%7B1kN%2Fm%5E2%7D%7BkPa%7D%29%20%3D18%5C%20kN%2Fm%5E2)
The gage pressure,
.
In lbf/in2
The absolute pressure,
![P_{abs}=18\ kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=2.6\ lbf/in^2](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18%5C%20kPa%28%5Cfrac%7B1.45%5Ctimes%2010%5E%7B-1%7D%5C%20lbf%2Fin%5E2%20%7D%7B1kPa%7D%20%29%3D2.6%5C%20lbf%2Fin%5E2)
The gage pressure,
![P_{gage}=-80kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=-11.6\ lbf/in^2](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B1.45%5Ctimes%2010%5E%7B-1%7D%5C%20lbf%2Fin%5E2%20%7D%7B1kPa%7D%20%29%3D-11.6%5C%20lbf%2Fin%5E2)
In psi,
The absolute pressure,
.
The gage pressure,
![P_{gage}=-80kPa(\frac{1.45037738\times 10^{-1}\ psi }{1kPa} )=-11.6030\ psi](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B1.45037738%5Ctimes%2010%5E%7B-1%7D%5C%20psi%20%7D%7B1kPa%7D%20%29%3D-11.6030%5C%20psi)
In mm Hg
The absolute pressure,
![P_{abs}=18kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})= 135\ mm\ of\ Hg](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18kPa%28%5Cfrac%7B7.5%5C%20mm%5C%20of%5C%20Hg%20%7D%7B1%5C%20kPa%7D%29%3D%20135%5C%20mm%5C%20of%5C%20Hg)
The gage pressure,
![P_{gage}=-80kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})=-600\ mm\ of\ Hg](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B7.5%5C%20mm%5C%20of%5C%20Hg%20%7D%7B1%5C%20kPa%7D%29%3D-600%5C%20mm%5C%20of%5C%20Hg)
Answer:
balloon pushes you back
Explanation:
3rd Law: Every action has an equal and opposite reaction
So, when you let go of the balloon it's pushed forward so the balloon pushes you back
Answer:
false. it's positive terminal of an electric cell
I think its between b or c