All categories

3 years ago

7) The acceleration due to gravity near the surface of Mars is about one-third of the value

Physics

1 answer:

Doss [256]3 years ago

8 0

Answer:

C) three times slow than on earth

You might be interested in

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

mel-nik [20]

Answer:

Explanation:

All the displacement will be converted into vector, considering east as x axis and north as y axis.

5.3 km north

D = 5.3 j

8.3 km at 50 degree north of east

D₁= 8.3 cos 50 i + 8.3 sin 50 j.

= 5.33 i + 6.36 j

Let D₂ be the displacement which when added to D₁ gives the required displacement D

D₁ + D₂ = D

5.33 i + 6.36 j + D₂ = 5.3 j

D₂ = 5.3 j - 5.33i - 6.36j

= - 5.33i - 1.06 j

magnitude of D₂

D₂²= 5.33² + 1.06²

D₂ = 5.43 km

Angle θ

Tanθ = 1.06 / 5.33

= 0.1988

θ =11.25 ° south of due west.

4 0

2 years ago

Why don't we feel pressure exerted by atmosphere?

ozzi

Crushing pressure. Human bodies are used to air pressure. The air pressure in our lungs, ears and stomachs is the same as the air pressure outside of our bodies, which ensures that we don't get crushed. Our bodies are also flexible enough to cope when the internal and external pressures aren't exactly the same.

6 0

3 years ago

A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s

JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of = 3.84 m/s

angle of the rain drop = 25°

tan θ = $\dfrac{v}{u}$

tan 25° = $\dfrac{v}{3.84}$

v =3.84 × tan 25°

v = 1.79 m/s

hence, the train is moving at the speed of v = 1.79 m/s

3 0

2 years ago

A 1200 kg aircraft going 30 m/s collides with a 2000 kg aircraft that is parked and they stick together after the collision and

Leno4ka [110]

Answer:

83.055 m

Explanation:

According to the given scenario, the calculation of skid distance is shown below:-

$S = \frac{1}{2} \times (u + v) \times t$

Where

u = 11.3

v = 0

t = 14.7

Now placing these values to the above formula,

So,

$S = \frac{1}{2} \times (11.3 + 0) \times 14.7$

= 83.055 m

Therefore for computing the skid distance we simply applied the above formula i.e by considering the all items given in the question

4 0

2 years ago

Give me more thank plz

spayn [35]

Ok bro you are going to have 1 more

8 0

2 years ago