An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass

Physics

1 answer:

telo118 [61]3 years ago

3 0

Answer:

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{6}{3} \\ = 2$

We have the final answer as

Hope this helps you

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Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance b

Annette [7]

Answer:

1.21m

Explanation:

If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

Using the expression;

Velocity v = frequency f × wavelength ¶

Given frequency = 280Hz, speed of sound v = 338m/s

Substituting this data's in the expression given to get the wavelength will give;

¶ = v/f

¶ = 338/280

¶ = 1.21m

The smallest separation between the speakers that will produce the interference is 1.21m

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4 years ago

The weights in atwoods machine, starting at rest, attain a velocity of 2ft/sec in one sec. Find the ratio of the masses

Orlov [11]

Refer to the figure shown below.
Let m₁ and m₂ e the two masses.
Let a = the acceleration.
Let T = tension over the frictionless pulley.

Write the equations of motion.
m₂g - T = m₂a (1)
T - m₁g = m₁a (2)

Add equations (1) and (2).
m₂g - T + T - m₁g = (m₁ + m₂)a
(m₂ - m₁)g = (m₁ + m₂)a

Divide through by m₁.
(m₂/m₁ - 1)g = (1 + m₂/m₁)a

Define r = m₂/m₁ as the ratio of the two masses. Then
(r - 1)g = (1 +r)a
r(g-a) = a + g
r = (g - a)/(g + a)

With = 2 ft/s from rest, the acceleration is
a = 2/32.2 = 0.062 ft/s²
Therefore
r = (32.2 - 0.062)/(32.2 + 0.062) = 0.9962

Answer:
The ratio of masses is 0.9962 (heavier mass divided by the lighter mass).