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3 years ago

An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass

Physics

1 answer:

telo118 [61]3 years ago

3 0

Answer:

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{6}{3} \\ = 2$

We have the final answer as

Hope this helps you

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A visitor is staying in a tent that is 11 kilometers west of the closest point on a shoreline to a coral reef. The coral reef is

Vaselesa [24]

Answer:

Explanation:

From the question, it says that their tent is 11 km away from the shore which is also 3 km away from the coral reef. Essentially, the tent us 11 + 3 km away from the coral reef, and that's 14 km. He has to run at a rate of 7 know to cover an 11 km length and swim at 2 kmph to cover a 3 km length.

All the visitor needs to do is run more than 7 kmph to reduce the days time. For example, running at 11 kmph takes him or her exactly 1 hour to reach the shore, before taking another swim of about an hour to reach the reef

4 0

3 years ago

a body is projected at an angle of 30 degrees to the horizontal with a velocity of 15m/s, calculate the time it takes to reach t

andreev551 [17]

Explanation:

The vertical component the velocity of the projectile is 15 m/s x sin 30 = 7.5 m/s.

The body is accelarating downwards at 10 m/s^2.

This means that every second its upward velocity reduces by 10 m/s.

So if the body is travelling upwards at 7.5 m/s then how long does it take for the velocity to become 0?

(7.5 m/s) / (10 m/s^2) = 0.75 s

3 0

3 years ago

What is the smallest particle that relains<br> the properties of an element

VLD [36.1K]

Answer:

atom

Explanation:

Smallest particle of an element that identifies that element is an atom.

8 0

2 years ago

An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and

Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0

4 years ago

the mass of earth is 5.972 * 1024 kg, and the radius of earth is 6,371 km. a 750 kg satellite orbits 35,800 km above earth in a

adelina 88 [10]

The speed or the tangential velocity of the satellite to keep it in its orbit is 3,073.5 meters per second.

The gravitational force between two objects is given by:

F = GMm/r²

Where:

G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²

M, m = mass of each object

r = distance between objects

Parameters given in the problem:

M = 5.972 x 10²⁴ kg

m = 750 kg

r = 6371 + 35,800 = 42,171 km = 42,171,000 m

Hence,

F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²

= 168.1 N

This is equal to centripetal force:

F = m . v² / r

168.1 = 750 . v² / 42,171,000

v² = 9,446,304

v = 3,073.5 m/s

Hence, the tangential velocity of the satellite to keep it in its orbit is 3,073.5 m/s

Learn more about gravitational force here:

brainly.com/question/23504494

#SPJ4

5 0

1 year ago