All categories

3 years ago

What layer is just below the Earth’s crust?

1 answer:

4 0

I believe the answer you’re looking for is the mantle.

It goes inner core, outer core, mantle, crust,
from the very inside to the outside. I hope this is enough of a detailed reply to completely answer your question! Have a great night.

~Brooke❤️

You might be interested in

Which two statements are true about a system?

weqwewe [10]

Answer:The correct options are:

1. A system is a group of objects analyzed as one unit.

2. Energy that moves across system boundaries is conserved.

Explanation:

A system is defined as group of interrelated or interacting items existing as a single unit or a whole to achieve a specific objective.Energy lost by the system is equal to the energy gained by the surroundings.

Two statements are true about a system:

A system is a group of objects analyzed as one unit.
Energy that moves across system boundaries is conserved.

3 0

3 years ago

Read 2 more answers

The average weight of a particular box of crackers is 26.0 ounces with a standard deviation of 0.5 ounce. The weights of the

Olenka [21]

Answer:

(a) 99.865%

(b) 0.135%

Explanation:

Given that the weight of the boxes are normally distributed.

The average weight of the particular box,

$\mu=26.0$ ounce

The standard deviation of weight,

$\sigma=0.5$ ounce.

Let $z$ be the standard normal variable,

$z=\frac{x-\mu}{\sigma}$

And, the probability of the boxes having weight x ounces is

$P(z)=\frac{1}{2\pi}e^{-\frac{z^2}{2}}$

For $x=24.5$ ,

$z=\frac{x-\mu}{\sigma}=\frac{24.5-26}{0.5}=-3$

(a) For the boxes having weight more than 24.5 ounces: $z>-3$

So, the probability of boxes for $z>-3$ is

$P(z>-3)=\int_{-3}^{\infty}\left(\frac{1}{2\pi}e^{-\frac{z^2}{2}}\right)dx$

=0.99865

So, the percent of the boxes weigh more than 24.5 ounces is 99.865%.

(b) For the boxes having weight less than 24.5 ounces: z<-3

So, the probability of boxes for z<-3 is

$P(z-3}=1-0.99865$

=0.00135

So, the percent of the boxes weigh more than 24.5 ounces is 0.135%.

8 0

4 years ago

The maximum potential energy of a spring system (mass 15 kg, spring constant 850 N/m) is 6.5 J. a) What is the amplitude of the

Bumek [7]

Answer:

a) 0.124 m

b) 0.93 ms⁻¹

c) 0.5 k A² cos ² ( ωt )

Explanation:

1) Potential energy = U = 0.5 k A² , where A is the amplitude and k = 850 N/m is the spring constant.

0.5 ( 850) (A² ) = 6.5

⇒ A = 0.124 m = Amplitude.

b) From energy conservation, 0.5 m v² = 6.5

⇒ speed = v = 0.93 ms⁻¹

c) If x = A cos ωt ,

Potential energy = 0.5 k A² = 0.5 k A² cos ² ( ωt )

8 0

3 years ago

Compare the kinetic energy of a 20,000-kg truck moving at 110 km/h with that of an 80-kg astronaut in orbit moving at 27,500 km/

Ivahew [28]

for the truck :

M = mass of the truck = 20000 kg

V = speed of truck = 110 km/h = 110 (km/h) (1000 m/1 km) (1 h/3600 sec) = 30.6 m/s

kinetic energy of truck is given as

KE₁ = (0.5) M V²

inserting the values

KE₁ = (0.5) (20000) (30.6)² = 9363600 J

for the astronaut :

m = mass of astronaut = 80 kg

v = speed of astronaut = 27500 km/h = 27500 (km/h) (1000 m/1 km) (1 h/3600 sec) = 7638.9 m/s

kinetic energy of astronaut is given as

KE₂ = (0.5) m v²

inserting the values

KE₂ = (0.5) (80) (7638.9)²

KE₂ = 2.33 x 10⁹ J

Ratio of kinetic energy of truck with kinetic energy of astronaut is given as

KE₁ /KE₂ = (9363600)/(2.33 x 10⁹)

KE₁ /KE₂ = 0.00402

kinetic energy of truck is 0.00402 time the kinetic energy of astronaut.

7 0

3 years ago

What is the relationship between Avogadro's number and a mole?

Shtirlitz [24]

Answer:

A. There are 6.02 x 1023 items in a mole, which equals Avogadro's

number

Explanation:

The mole of a substance is

8 0

3 years ago