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ludmilkaskok [199]
3 years ago
8

What layer is just below the Earth’s crust?

Physics
1 answer:
Elenna [48]3 years ago
4 0
I believe the answer you’re looking for is the mantle.

It goes inner core, outer core, mantle, crust,
from the very inside to the outside. I hope this is enough of a detailed reply to completely answer your question! Have a great night.

~Brooke❤️
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A person stands at the base of a hill that is a straight incline making an angle φ with the horizontal. For a given initial spee
Brums [2.3K]

Answer:

θ = sin⁻¹\sqrt{2gd}

Explanation:

From one of the equations of motion, v² = u² + 2as.......... equation 1

Since the object thrown was moving against gravity, then the acceleration, a would change to -g and the initial velocity u would change to V₀ sin θ because the object is travelling at angle of θ to the horizontal. By inputting all these parameter into equation 1, we would arrive at:

v² = (u sin θ)² - 2gd

(u sin θ)² = 2gd

d = (u sin θ)²/2g

sin² θ = 2gd

sin θ = \sqrt{2gd}

θ = sin⁻¹ \sqrt{2gd}

4 0
3 years ago
How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?
4vir4ik [10]

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

5 0
2 years ago
A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti
Sergeeva-Olga [200]

Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

                       =       (49 / 5)  m/s  /  s

                       =            9.8 m/s² 
8 0
2 years ago
Read 2 more answers
a 0.40kg soccer ball approaches a player horizontally with a velocity of 18m/s north. the player strikes the ball and causes it
denis23 [38]
Impulse = Ft = (m)(delta v)
delta v = change in velocity = velocity final - velocity initial.
= -22m/s - +18m/s = -40m/s.
mdeltav = (0.40kg)(-40m/s) = -16kgm/s or -16Ns.

4 0
3 years ago
How would you describe the motion of all three vehicles?​
Angelina_Jolie [31]

Answer:In physics, motion is defined as a change in the position of a body with respect to a reference point. ... Think about the motion of three cars: one in the fast-moving carpool lane, another in the middle lane, and the third in the slow lane used to enter or exit the freeway.

Explanation:

3 0
3 years ago
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