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ivolga24 [154]
4 years ago
12

Which travels faster: a car that travels 6 miles in 10 minutes at a constant speed, or a train that travels 6 miles in 8 minutes

at a constant speed? Explain how
you
Mathematics
1 answer:
zubka84 [21]4 years ago
4 0

Answer: 29 :)

Step-by-step explanation:

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The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in sec
pashok25 [27]

Answer:

Step-by-step explanation:

<h2><u>Part A</u></h2>

in interval ( 0 ; 2)

<h2><u>Part B</u></h2>

in interval (2; 4)

<h2><u>Part C</u></h2>

in interval  (4 ; 6 )

<h2><u>Part D</u></h2>

The graph shows that at first the ball rises up ; and then it is seen that it goes down and loses height to zero , from which it can be concluded that the height after 10 seconds remains unchanged and therefore the height of the ball after 16 seconds will be zero

6 0
3 years ago
Simplify (7 1/5)5<br> Please show work
Westkost [7]

7 ^ 1/5 ^ 5

power to a power is multiplied

7 ^ (1/5 *5)

7^1

7

Choice A

5 0
3 years ago
Read 2 more answers
Please tell me how to write it on the paper thank you
frez [133]

Answer: which problem is it ?

Step-by-step explanation:

4 0
3 years ago
What are the x and y intercept for the graph of 4x - 3y = -12
Mama L [17]

Answer:

(-3,0) = x and (0,4) = y

Step-by-step explanation:

7 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
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