Chen connects several lightbulbs in a series circuit. Electricity flows through the circuit, and all the bulbs light up.
1 answer:
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Answer: a) 1 b) 61 W c) 61 W
Explanation:
a) The Power Factor (also known as cos φ), is defined by the difference in phase between current and voltage, in a RLC series circuit, and is expressed as follows:
cos φ = R / Z = R /
In resonance, XL =XC, so the circuit behaves like it were purely resistive, so Z=R.
Replacing in the expression for power factor, we have:
cos φ = R/Z = R/R = 1
This means that in resonance, current and voltage are in phase each other.
b) The average power delivered by the source, in resonance, is simply the power dissipated at the resistance R, as follows:
Pavg = V² rms / R = V₀² / √2 / R = 61 W
c) If the circuit remains in resonance, the average power , which does not depends on frequency provided this condition remains, keeps the same, i.e. , 61 W.
Answer:
It is real, inverted, and smaller than the object.
Explanation:
Let's start by using the lens equation to find the location of the image:
where we have:
q = ? is the distance of the image from the lens
f = 15 cm is the focal length (positive for a converging lens)
p = 50 cm is the distance of the object from the lens
Solving the equation for q, we find
The sign of q is positive, so the image is real.
Now let's also write the magnification equation:
where
are the size of the image and of the object
By substituting p = 50 cm and q = 21.3 cm, we find
So we notice that:
: this means that the image is smaller than the object
: this means that the image is inverted
so, the correct option is:
It is real, inverted, and smaller than the object.