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kow [346]
3 years ago
13

A. Semi-annually: B. Quarterly: C. Monthly: Please help:)

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0
Quarterly or monthly because semi annually is to soon do I think monthly
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Find the area of the trapezoid when height = 5in, base1 = 12in, and base2 = 15in.
myrzilka [38]
A= (a+b)/2*h
A=(12+15)/2*5
A=(27/2)*5
A=13.5*5
A=67.5in
5 0
3 years ago
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Lostsunrise [7]

Answer:A

Step-by-step explanation:

8 0
2 years ago
The two triangles are similar.
Andrei [34K]

Answer:

x=10

Step-by-step explanation:

The two triangles are similar since each triangle is the same shape of right triangle but different sizes. To find x, write a proportion between two equal ratios of side lengths.

\frac{28}{20}=\frac{4x+2}{3x}

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3 years ago
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Given the hyperbola y = 1/x, find the area under the curve between x = 5 and x = 33 to 3 sig. dig. namely: integral subscript 5
Shtirlitz [24]

Answer:

(b) ln(33/5)

Step-by-step explanation:

\int\limits_{5}^{33}  \frac{1}{x} \, dx = \ln(x)  \Big|\limits_{5}^{33} = \ln(33) - \ln(5) \\\\= ln(33/5)

Remember that  in general

\ln(a) - \ln(b) = \ln(a/b)

4 0
2 years ago
A bank security camera is mounted on a wall. The camera is set at an angle of depression of 19 degrees so that it is focused on
777dan777 [17]

Answer:

8.95feet

Step-by-step explanation:

The set up is a right angled triangle where;

The camera's horizontal distance from the focus point = 26feet = Adjacent;

The height of the camera above the floor = Opposite = x

Angle of elevation = 19°

According to TOA in trig identity;

Tan theta = opp/adj

Tan 19 = x/26

x = 26tan 19

x = 26(0.3443)

X = 8.95feet

Hence the camera is placed at a height of 8.95feet above the floor

7 0
2 years ago
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