Answer:
The energy dissipated as the puck slides over the rough patch is 1.355 J
Explanation:
Given;
mass of the hockey puck, m = 0.159 kg
initial speed of the puck, u = 4.75 m/s
final speed of the puck, v = 2.35 m/s
The energy dissipated as the puck slides over the rough patch is given by;
ΔE = ¹/₂m(v² - u²)
ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)
ΔE = -1.355 J
the lost energy is 1.355 J
Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J
Answer:
220 V
Explanation:

As the resistors are connected in series,

= 20 + 30 + 60
= 110 ohms
V = IR
= 2 * 110
= 220 V
Hope it helps
The formula for Fahrenheit and Celsius conversion is
T(°F)<span> = </span>T(°C)<span> × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
</span>This means that keeping this FORMULA in mind we can add different values to it and accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C using F = (0 x 1.8) + 32
Universe contains billions and billions of stars, galaxies, planets, asteroids, comets and many more different type of bodies. These objects emit radiations of varied frequency. In order to study these different kind of objects, different kind of technology is required. There are different type of missions: some contain probes which land on the surface, some orbit the bodies etc. These are for solar system. Yet some are space observatories having detectors to study light from distant objects. Further, there are different detectors for different wavelengths of electromagnetic spectrum.
Answer: 1100 ft lb/s and 2 H.P
Explanation:
To calculate for the power developed in the elevator motor in ft.lb/s, we multiply the distance and the weight of the elevator and divide the product by the time.
Power = (10 ft)(2200 lb) / 20 s = 1100 ft.lb/s
Next, convert the calculated value to HP.
1100 ft.lb/s x (1 HP/ 550 ft.lb/s) = 2 HP
hope this helps please give brainliest!