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Kruka [31]
3 years ago
11

A light year is approximately 9.5 million km long. 'Barnard's Star' is 6 light years away from Earth. Calculate how many million

s of kilometres this is.
Physics
2 answers:
hammer [34]3 years ago
7 0

Answer:

6 light years = 57 million km

Explanation:

Given;

A light year = 9.5 million km

To calculate how far is 6 light years;

6 light years = 6 × 1 light year = 6 × 9.5 million km

6 light years = 57 million km

denpristay [2]3 years ago
3 0

Answer:

57 million kilometres

Explanation:

We are given that:

1 light year = 9.5 million kilometres

To get 6 light years, we simply multiply 6 by 9.5 million kilometres:

6 light years = 6 * 9.5 million= 57 million kilometres

St Bernard's star is 57 million kilometres away from the earth.

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Answer:

Comparison has been made.

Explanation:

Consider perfectly inelastic collision.Two masses of m1 and m2 with initial velocities u1 and u2 before colliding, stick together after collision and move with common speed v. then according to the rule of momentum preservation

m1u1+m2u2=  (m1+m2)v

v= \frac{m1u1+m2u2}{m1+m2}

If u1 and u2 are known the final common velocity can be determined

Initial kinetic energy is

\frac{1}{2}m1u1^{2}+\frac{1}{2}m2u2^{2}

The collion here is perfectly inelastic this means kinectic energy is not conserved. Therefore, initial kinectic energy is not equal to final kinectic.  

\frac{1}{2}m1v^{2}+\frac{1}{2}m2v^{2}

4 0
2 years ago
What should you do in the intermediate steps of a numerical calculation?
neonofarm [45]

Answer:

The answer is "Keep at least a couple of extra digits beyond those needed for determining significant figures."

Explanation:

3 0
2 years ago
Which equation relates charge, time, and current?
san4es73 [151]

Answer:

The first one

Explanation:

8 0
3 years ago
How much heat in joules is required to melt an ice cube with a mass of 18.6 g at 0 °C? The Lf for water is 333 J/g.
EastWind [94]

Answer:

The heat energy required, Q = 6193.8 J

Explanation:

Given,

The mass of ice cube, m = 18.6 g

The heat of fusion of ice, ΔHₓ = 333 J/g

The heat energy of a substance is equal to the product of the mass and heat of fusion of that substance. It is given by the equation,

                               <em> Q = m · ΔHₓ     joules</em>

Substituting the given values in the above equation

                                Q = 18.6 g x 333 J/g

                                    = 6193.8 J

Hence, the heat required to melt the ice cube is, Q = 6193.8 J

5 0
3 years ago
A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. How long was the ball in the air? Rou
Slav-nsk [51]

Answer:

3.6 seconds

Explanation:

Given:

y₀ = y = 0 m

v₀ = 31 sin 35° m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 = 0 + (31 sin 35°) t + ½ (-9.8 m/s²) t²

0 = 17.78t − 4.9t²

0 = t (17.78 − 4.9t)

t = 0 or 3.63

Rounded to the nearest tenth, the ball lands after 3.6 seconds.

4 0
3 years ago
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