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Kruka [31]
3 years ago
11

A light year is approximately 9.5 million km long. 'Barnard's Star' is 6 light years away from Earth. Calculate how many million

s of kilometres this is.
Physics
2 answers:
hammer [34]3 years ago
7 0

Answer:

6 light years = 57 million km

Explanation:

Given;

A light year = 9.5 million km

To calculate how far is 6 light years;

6 light years = 6 × 1 light year = 6 × 9.5 million km

6 light years = 57 million km

denpristay [2]3 years ago
3 0

Answer:

57 million kilometres

Explanation:

We are given that:

1 light year = 9.5 million kilometres

To get 6 light years, we simply multiply 6 by 9.5 million kilometres:

6 light years = 6 * 9.5 million= 57 million kilometres

St Bernard's star is 57 million kilometres away from the earth.

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(a) Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t)
dolphi86 [110]

Answer:

r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k

Explanation:

a(t)=20t i+sin(t) j +cos(2t) k

v(t)=\int\limits^a_b {a(t)} \, dt

=(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k---------------eqn 1

given v(0)=i

i=c_1i+(-1+c_2)j+(0+c_3)k

c_1=1   c_2=1  c_3=0

from equation 1

V(t)=(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k----------eqn 2

now r(t)=\int\limits^a_b {v (t)} \, dt

(\frac{10t^3}{3}+t+c_1)i+(-sint+t+c_2)j+(\frac{-cos2t}{4}+c_3)k

given r(0)=j

0i+1j+ok = c_1i+c_2j+(\frac{-1}{4}+c_3)k

c_1=0  c_2=0  c_3 =  \frac{1}{4}

r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k

8 0
3 years ago
What is the strength of an electric field that will balance the weight of a 3.3 g plastic sphere that has been charged to -7.6 n
sp2606 [1]

As the plastic sphere is charged, therefore it experience an electric force when placed in an electric fields and also experiences gravitational force acts downward so the electric force must act upward.

Let  F_{E} is electric force and F_{G} is gravitational force.

If these forces are balanced, thereforeF_{E} = F_{G}

or                                                                      \left | q \right |E=mg\\\\\ E=\frac{mg}{\left | q \right |}

Given, q=-7.6 nC=-7.6\times10^{-9} C and  m=3.3 g= 3.3\times10^{-3} kg.

Substituting these values in above equation we get,

E=\frac{3.3\times10^{-3} kg\times9.8 m/s^{2} }{7.6\times10^{-9} C}\\\\E=4.2\times10^{6} N/C

Thus, the magnitude of electric field is 4.2\times10^{6} N/C.

As the charge is negative, the electric field at the location of the plastic sphere must be pointing downward.



8 0
3 years ago
A small particle starts from rest from the origin of an xy-coordinate system and travels in the xy-plane. Its acceleration in th
CaHeK987 [17]

Answer:

The x-coordinate of the particle is 24 m.

Explanation:

In order to obtain the x-coordinate of the particle, you have to apply the equations for Two Dimension Motion

Xf=Xo+Voxt+0.5axt²(I)

Yf=Yo+Voyt+0.5ayt² (II)

Where Xo, Yo are the initial positions, Xf and Yf are the final positions, Vox and Voy are the initial velocities, ax and ay are the accerelations in x and y directions, t is the time.

The particle starts from rest from the origin, therefore:

Vox=Voy=0

Xo=Yo=0

Replacing Yf=12, Yo=0 and Voy=0 in (I) and solving for t:

12=0+(0)t+ 0.5(1.0)t²

12=0.5t²

Dividing by 0.5 and extracting thr squareroot both sides:

t=√12/0.5

t=√24 = 2√6

Replacing t=2√6, ax=2.0,Xo=0 and Vox=0 in (I) to obain the x-coordinate:

Xf=0+0t+0.5(2.0)(2√6)²

Xf= 24 m

5 0
3 years ago
In the image below, which objects would have a greater gravitational force between them, Objects A and B, or Objects B and C? Gi
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I don't see an image, but the force of gravity depends on mass and distance. If the mass and the distance are different, you divide (mass÷distance).the greater the number the greater the force of gravity.

Tell me if you need more info.
4 0
3 years ago
The students in a class had the following scores on a test:
Brilliant_brown [7]
C. 76 I just did the question earlier
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3 years ago
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