A 762 kg car experiences a braking force of 9045 N and skids to a stop in 4.3 seconds. What is the speed of the car just before
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Answer:
h = 15.34 m
Explanation:
given,
tuning fork vibration = 513 Hz
speed of sound = 343 m/s
frequency after deflection = 489 Hz
the source (the fork) moves away from the observer, its speed increases and hence the apparent frequency decreases
u = 16.92 m/s
height of the building
v² = u² + 2 g s
16.92² = 2 x 9.8 x h
h = 14.61 m
time taken by sound to reach observer
in this time tuning fork has fallen one more now,
h' = 0.7296 m = 0.73 m
total distance
h = 14.61 + 0.73
h = 15.34 m
Horizontal speed = 24.0 m/s
height of the cliff = 51.0 m
For the initial vertical speed will are considering the vertical component. Therefore,
Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means
let's find how long the ball remained in the air.
Finally, let's find the how far from the base of the building the ball landed(horizontal distance)