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3 years ago

Derive a relation between Universal Gravitational Constant (G) and Acceleration due to gravity(g)?

2 answers:

5 0

<span>suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2 ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2</span>

snow_tiger [21]3 years ago

4 0

Suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2 ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2

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Len [333]

The motorbike reaches 100 km/h in 3.5 seconds

Explanation:

The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the motorbike in this problem,

u = 0 (it starts from rest)

$v = 100 km/h = 27.8 m/s$ is the final velocity

$a=7.9 m/s^2$ is the acceleration

Solving for t, we find the time it takes for the bike to reach that velocity:

$t=\frac{v-u}{a}=\frac{27.8-0}{7.9}=3.5 s$

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3 years ago

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Lesechka [4]

Answer:

A fuse and circuit breaker both serve to protect an overloaded electrical circuit by interrupting the continuity, or the flow of electricity. ... Fuses tend to be quicker to interrupt the flow of power, but must be replaced after they melt, while circuit breakers can usually simply be reset.

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Solution :

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3 years ago

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3 years ago

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Reil [10]

Answer:

hi there

Explanation:

1 - III

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3 years ago

Read 2 more answers