Answer
16.25
Step-by-step explanation: <em><u>To The Nearest Hundredth</u></em>
(-1, 2), (3, 1)
<u>√17</u>
(3, 1), (7, 2)
<u>√17</u>
(3, 1), (7, 2)
<u>√8</u>
So our answer is =
<u>8 + √17 + √17 = 16.25</u>
<u>hope it works for you!</u>
Answer:
Part 1) The area of the circle is 
Part 2) The circumference of the circle is 
Step-by-step explanation:
step 1
The area of a circle is equal to

we have
---> the radius is half the diameter

substitute


step 2
The circumference of a circle is equal to

we have

substitute


A^2 + 3b + c - 2d
(3)^2 + 3(8) + (2) - 2(5)
9 + 24 + 2 - 10 = 25
Answer:
-10
Step-by-step explanation:
2*-2=-4
3*-5=-15
1-(-4)+(-15)=-10
We want to determine the domain of

any function of the form

is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.
The domain of such functions is all real numbers.
That is for any x, the expression <span>3(2^-x) "makes sense".
Answer: </span><span>The domain is all real numbers</span>