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Lapatulllka [165]
3 years ago
11

Agrocery store sells brand a olive oil in a 33-fluid-ounce bottle for $16.50. the store also sells brand b olive oil in a large

dispenser that customers can buy for $4.80 per cup.
Mathematics
1 answer:
Ivan3 years ago
4 0
Brand A olive oil is cheaper, if that’s the question
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Which of the following is the equation for the line perpendicular to the line y=−x+20 that passes through the point (−4, 2)?
coldgirl [10]
I have a feeling it’s a but I’m not that sure good luck might want to wait on other peoples opinions
7 0
3 years ago
Gillian purchased 25 books at the library book sale. each hardcover book cost $1.50, and each paperback book cost $0.50. gillian
Sindrei [870]
H + p  = 25
1.50 h + 0,50 p = 26.50
___________________
p = 25 - h
1.50 h + 0.50 ( 25 - h ) = 26.50
1,50 h + 12.50 - 0.50 h = 26.50
h = 26.50 - 12.50 
h = 14
p = 25 - 14
p = 11
Gillian purchased 14 hardcover books and 11 paperback books.
3 0
4 years ago
Compare -3.6 and 1.2.
jasenka [17]

Answer:

-3.6 is a negative number compared to 1.2. 1.2 is -3 times less than -3.6. -3.6 is -3 times more than 1.2

Step-by-step explanation:

(can I get brainliest)

8 0
3 years ago
Read 2 more answers
A veterinarian’s assistant made a table that shows the animals seen in the office in one week. What is the probability that the
horsena [70]

Answer:

The probability that the pet seen was sick is 53.57%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ration of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Here,

n (E) = number of favorable outcomes

N = total number of outcomes

Denote the events as follows:

<em>C</em> = the pet is a cat

<em>D</em> = the pet is a dog

<em>O </em>=<em> </em>the pet is some other animal

<em>S</em> = the pet is sick.

The data provided is summarized as follows:

n (C) = 28

n (C ∩ S) = 3

n (D) = 42

n (B ∩ S) = 4

n (O) = 24

n (O ∩ S) = 8

Compute the probability that a cat was sick as follows:

P(C\cap S)=\frac{n(C\cap S)}{n(C)}=\frac{3}{28}

Compute the probability that a dog was sick as follows:

P(D\cap S)=\frac{n(D\cap S)}{n(D)}=\frac{4}{42}=\frac{2}{21}

Compute the probability that another animal was sick as follows:

P(O\cap S)=\frac{n(O\cap S)}{n(O)}=\frac{8}{24}=\frac{1}{3}

Compute the probability that the pet seen was sick as follows:

P (S) = P (C ∩ S) + P (D ∩ S) + P (O ∩ S)

       =\frac{3}{28}+\frac{2}{21}+\frac{1}{3}\\=\frac{9+8+28}{84}\\=\frac{45}{84}\\=0.5357

Thus, the probability that the pet seen was sick is 53.57%.

8 0
3 years ago
Read 2 more answers
Amelia sent an equal number of messages each day for one week. At the end of the week, she had sent 49 messages. How many messag
ella [17]

Answer:

7

Step-by-step explanation:

There are 7 days in a week, and she sent 49 messages by the end of the week. Assuming that she sent the same number of messages each day, we would take the number of messages and divide it by the number of days, 49 and 7. 49 divided by 7 is 7. She sent 7 messages each day!

Hope this helps, brainliest always appreciated haha

6 0
3 years ago
Read 2 more answers
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