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3 years ago

What would be the coordinates of A(−9,12)

Mathematics

1 answer:

hammer [34]3 years ago

4 0

Answer:

(12, 9)

Step-by-step explanation:

I am assuming it was rotated about the origin.

180 degrees clockwise would give the point ((9, 12).

Then if this point is roated 90 degrees anti-clockwise it would end up at the point (12,9)

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nataly862011 [7]

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2 years ago

Edgar pay $67.86 for 7.8 pounds of fertilizer. What is the price per pound of fertilizer?

prohojiy [21]

Answer:

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3 years ago

Write and equation in slope intercept form of a line that has a slope of 1/3 and passes through the point (6,0)

ladessa [460]

y=(1/3)x-2

Step-by-step explanation:

the slope-intercept form is y-y1=m(x-x1)

hence, y-0=1/3(x-6) or y=(1/3)x-2

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2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

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3 years ago

Un tanque de 60 litros de agua se llenó solo hasta los 3 quintos de su capacidad ¿cuántos litros de agua hay en el tanque?

Romashka [77]

180 litros de agua en el tanque

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3 years ago