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lakkis [162]
3 years ago
14

Why did it require two sodium atoms to complete the Na2O formula unit? Na has +2 charge and O has -1 charge. Na has +1 charge an

d O has -2 charge. Na has -2 charge and O has +1 charge.
Chemistry
2 answers:
Darya [45]3 years ago
7 0

Answer:

B

Explanation:

Edg2020

Artyom0805 [142]3 years ago
5 0
Na₂O is an ionic compound. Na is in group 1 which means it has one electron in the outer shell. O is in group 6 so it has 6 electrons in the outer shell.
To become stable atoms need to either lose the electrons in the outer shell or gain electrons to gain a complete outer shell configuration. 
To become stable Na loses its outer electron and becomes positively charged. It only loses one electron, so net charge is +1. O to become stable gains 2 electrons to complete its outer shell and becomes negatively charged. since it gains 2 electrons, the net charge is -2. 
cation - Na⁺
anion - O²⁻
O gains 2 electrons but Na can give only one electron, therefore 2 Na⁺ ions are required. 
the compound can be written by exchanging the charges
  ions         Na⁺       O²⁻
charge       +1       -2
exchange   Na₂O
Correct answer is <span>Na has +1 charge and O has -2 charge</span>
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What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi
insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

          E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}

                             = 0.535 - 1.065

                             = - 0.53 V

Also, it is known that relation between E^{o}_{cell} and K is as follows.

            E^{o}_{cell} = \frac{RT}{nF} \times ln K

                 ln K = \frac{nFE^{0}_{cell}}{RT}      

Substituting the given values into the above formula as follows.

                 ln K = \frac{nFE^{0}_{cell}}{RT}    

                        =  \frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}  

                ln K = -41.28

                    K = e^{-41.28}    

                        = 1 \times 10^{-18}

Thus, we can conclude that the value of the equilibrium constant for the given reaction is 1 \times 10^{-18}.      

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3 years ago
How can all chemical compounds be classified?
ale4655 [162]
Organic or inorganic is the answer
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3 years ago
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Use the mass and volume data to calculate the density of mercury to the nearest tenth. Mass of mercury = 57 g Volume of mercury
Elena-2011 [213]

Density = mass/volume = 57g/4.2 mL ≈ 13.6 g/mL

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How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

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2 years ago
Plants absorb the greenhouse gas carbon dioxide during the process of __.
Dvinal [7]

Answer:

during the process of carbon cycle

7 0
3 years ago
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