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lakkis [162]
3 years ago
14

Why did it require two sodium atoms to complete the Na2O formula unit? Na has +2 charge and O has -1 charge. Na has +1 charge an

d O has -2 charge. Na has -2 charge and O has +1 charge.
Chemistry
2 answers:
Darya [45]3 years ago
7 0

Answer:

B

Explanation:

Edg2020

Artyom0805 [142]3 years ago
5 0
Na₂O is an ionic compound. Na is in group 1 which means it has one electron in the outer shell. O is in group 6 so it has 6 electrons in the outer shell.
To become stable atoms need to either lose the electrons in the outer shell or gain electrons to gain a complete outer shell configuration. 
To become stable Na loses its outer electron and becomes positively charged. It only loses one electron, so net charge is +1. O to become stable gains 2 electrons to complete its outer shell and becomes negatively charged. since it gains 2 electrons, the net charge is -2. 
cation - Na⁺
anion - O²⁻
O gains 2 electrons but Na can give only one electron, therefore 2 Na⁺ ions are required. 
the compound can be written by exchanging the charges
  ions         Na⁺       O²⁻
charge       +1       -2
exchange   Na₂O
Correct answer is <span>Na has +1 charge and O has -2 charge</span>
You might be interested in
All atoms of an element have the same number of ________. electrons neutrons protons protons plus neutrons
Cloud [144]

Answer:

protons

Explanation:

An element, by definition, always has the same number of protons.  Sodium, element 11, has 11 protons.  Anything with 11 protons is a sodium atom, regardless of the number of neutrons, electrons, or politicians.  

6 0
2 years ago
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Please help. it’s my last question.
ale4655 [162]
<h3>Further explanation </h3>

Given

Atomic symbol

Required

Atomic composition

Solution

Atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Number of protons and Number of Neutrons  in nucleus

Number of electrons in the shell

From the picture:

protons = 3

neutrons = 4

electrons = 3

atomic number = protons = electrons = 3

mass number = protons + neutrons = 3+4 = 7

4 0
3 years ago
An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6
Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

Explanation : Given,

Initial volume of gas = 261.6\times 10^{-6}m^3

Final volume of the gas = 138.2\times 10^{-6}m^3

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

\Delta U=q+w

where,

\Delta U = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

q=-w

Thus, w = -q = 9340 J

The expression used for work done will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 9340 J

n = number of moles of gas  = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas

V_2 = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})

T=586.83K

Now we have to calculate the final pressure of the gas by using ideal gas equation.

PV=nRT

where,

P = final pressure of gas = ?

V = final volume of gas = 138.2\times 10^{-6}m^3=138.2\times 10^{-9}L

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)

P=1.046\times 10^{9}atm

Therefore, the temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

6 0
3 years ago
What mass of sucrose is needed to make 300.0 mL of a 0.5 M solution? (molar mass=<br> 342.34 g/mol)
Anuta_ua [19.1K]
I need points i’m sorry but yea lol good luck
7 0
3 years ago
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