The atmospheric pressure will be:
The pressure of the atmosphere resulting from the mercury column is 0.959 atm
What is atmospheric pressure?
The force that an object experiences from the weight of the air above it per unit area are known as atmospheric pressure.
Given: Height of mercury column = 729 mm Hg
To find: The pressure of the atmosphere
Calculation:
The atmospheric column resulting from the mercury column is calculated as follows:
1 atm =760 mm Hg
So, we can convert the 729 mm Hg to atm, and we get
Atmospheric pressure = 729 x 1 atm / 760 = 0.959 atm
Learn more about atmospheric pressure here,
brainly.com/question/14315894
#SPJ4
Answer:
temperature of the reaction vessel
Explanation:
temperature of the reaction vessel
Explanation:
According to the law of dilution,
The given data is as follows.
= 0.4782,
= ?
= 0.025
,
= 250 mL
Hence, we will calculate the value of
as follows.
=
= 13.07
Thus, we can conclude that we need 13.07 mL 0.4782 M sodium thiosulfate solution using pipette.
Answer:
46.761g/mol
Explanation:
Given parameters:
Element = Hilarium , Hi
Isotopes: Hi- 45, Hi-46 and Hi- 48
Natural abundance of Hi-45 = 18.3%
Hi-46 = 34.5%
Hi-48 = 47.2%
Unknown:
Atomic weight of naturally occurring Hilarium = ?
Solution:
Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.
We can use the expression below to find this value:
Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈
m is the atomic mass of each isotope and α is the abundance
Atomic weight = (45 x
) + (46 x
) + (48 x
)
Atomic weight of Hi = 8.235 + 15.870 + 22.656 = 46.761g/mol
The first step is to focus on the parent carbon chain:nonane. This indicates a carbon chain with 9 carbon atoms. From here, on the 4th carbon from one side, place a Br functional group; on the 2nd carbon, place a I functional group; on the 5th and 6th carbon, place a CH₃ (methyl) functional group to each. Lastly, complete the bonding with H atoms. The structure is shown in the attached picture.