Since neon is a noble gas we can easily assume its behaviour to be an ideal gas. In ideal gases pressure is said to be inversely proportional to volume,
at fixed temperature, this is Boyle's law.
Therefore we can use this law to state the following equation
P1V1/T1 = P2V2/T2
in this case temperature is fixed therefore it can be eliminated,
then,
P1V1 = P2V2
standard pressure (P1) is 101 325 Pa
V1 = 375 ml
P2 = 90 000 Pa
substituting these values,
101 325 Pa * 375 ml = 90 000 Pa * V2
V2 = 101 325 * 375 / 90 000
= 422.18 ml
After rounding off the final answer is option A - 422 ml
No. Just because it is a solid doesn't mean it has no motion. The only way for particles to be motionless is for the solid to reach Absolute Zero (0* K). Which is impossible. So, therefore, it is impossible for particles in a solid to be motionless.
The question is incomplete, here is the complete question:
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴
a) 2.099
b) 10.463
c) 3.546
d) 2.307
e) 3.952
<u>Answer:</u> The pH of the solution is 3.546
<u>Explanation:</u>
We are given:
Moles of formic acid = 0.370 moles
Moles of sodium formate = 0.230 moles
Volume of solution = 1 L
To calculate the molarity of solution, we use the equation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5BHCOONa%5D%7D%7B%5BHCOOH%5D%7D%29)
= negative logarithm of acid dissociation constant of formic acid = 3.75
![[HCOOH]=\frac{0.370}{1}](https://tex.z-dn.net/?f=%5BHCOOH%5D%3D%5Cfrac%7B0.370%7D%7B1%7D)
pH = ?
Putting values in above equation, we get:

Hence, the pH of the solution is 3.546
Answer:
It bonds with the added H+ or OH in solution.
Explanation: