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Yuki888 [10]
3 years ago
12

Why do Metals have high melting point and boiling points

Chemistry
1 answer:
hjlf3 years ago
6 0

As there is a strong electrostatic force of attraction between the positive metal ions and the negatively charged electrons, more energy is needed to overcome these forces of attractions and hence, high melting and boiling points

Hope this will help you

If so, do make this a brain lister :)

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A combustion reaction will always be associated with a change in entropy that will be:________.
Alex Ar [27]

Answer:

Option (A) : Positive

Explanation:

A combustion reaction will always be associated with a change in entropy that is Positive due to the gaseous products released. Hence, there is a large positive entropy change.

8 0
4 years ago
How many atoms are in 1.5 mole of iron?
Maslowich
How many iron atoms are present in a piece of iron weighing 95.8 g? , shows that its molecules contain one S atom and two O atoms; calculate its molar mass. molecules, which consist of 6.02 x 1023 S atoms and 2(6.02 x 1023) O atoms. S): Concept 4.
7 0
3 years ago
PREDICT THE PRODUCTS AND BALANCE THE EQUATION <br> FeCl2 (aq)+K2NO3 (aq)<br> →
Lyrx [107]

Answer:

see below

Explanation:

Swap cations and anions

K2NO3 is not balanced, it is either 2KNO3 or KNO3 and only 2KNO3 works in this case

FeCl2 (aq)+KNO3 (aq) → Fe(NO3)2 (aq) + 2KCL (aq)

3 0
3 years ago
Plz I need help with my chemistry homework jJnsjs​
professor190 [17]

answer

1.1 Carbon is the sixth element in the periodic table.

(IV A)

1.2 electric configuration: O⁸ (He²) 2s² 2p⁴ .

atomic number: 8

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3 0
3 years ago
10. A mountain bike's
sergij07 [2.7K]

Answer:

The energy stored in the spring when the bike goes over a bump is 6.6\times 10^{-3} joules.

Explanation:

Let suppose that spring has a linear behavious, by means of Hooke's Law, definition of Work and Work-Energy Theorem we find that the potential energy stored in the spring (U_{g}), measured in joules, is defined by:

U_{e} = \frac{1}{2}\cdot k\cdot x^{2} (1)

Where:

k - Spring constant, measured in newtons per meter.

x - Deformation, measured in meters.

If we know that k = 33\,\frac{N}{m} and x = 0.02\,m, the energy stored by the spring due to compression is:

U_{e} = \frac{1}{2}\cdot \left(33\,\frac{N}{m} \right) \cdot (0.02\,m)^{2}

U_{e} = 6.6\times 10^{-3}\,J

The energy stored in the spring when the bike goes over a bump is 6.6\times 10^{-3} joules.

8 0
3 years ago
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