Question

An ideal gas exerts a pressure of 3atm in a 3L container. The container is at a temperature of 298K.

Answer 1

Given:

Initial pressure P1 = 3 atm

Initial volume = 3L

Temperature (constant)= 298 K

final volume V2 = 2L

To find:

Final pressure P2 = ?

Solution:

According to Boyle's Law,

P1V1 = P2V2

3×3 = 2 × P2

P2 = 9/2

P2 = 4.5 atm

${Answer = 4.5 atm}$

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