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2 years ago

An ideal gas exerts a pressure of 3atm in a 3L container. The container is at a temperature of 298K.

Chemistry

1 answer:

zepelin [54]2 years ago

8 0

Given:

Initial pressure P1 = 3 atm

Initial volume = 3L

Temperature (constant)= 298 K

final volume V2 = 2L

To find:

Final pressure P2 = ?

Solution:

According to Boyle's Law,

P1V1 = P2V2

3×3 = 2 × P2

P2 = 9/2

P2 = 4.5 atm

${Answer = 4.5 atm}$

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36.8 g of CuSO4(s) was added to water to prepare a 2.00 L solution. What is the

Yuki888 [10]

Answer:

Option D. 0.115 M

Explanation:

The following data were obtained from the question:

Mass of CuSO4 = 36.8 g

Volume of solution = 2 L

Molar mass of CuSO4 = 159.62 g/mol

Molarity of CuSO4 =..?

Next, we shall determine the number of mole in 36.8 g of CuSO4.

This can be obtained as shown below:

Mass of CuSO4 = 36.8 g

Molar mass of CuSO4 = 159.62 g/mol

Mole of CuSO4 =.?

Mole = mass /Molar mass

Mole of CuSO4 = 36.8 / 159.62

Mole of CuSO4 = 0.23 mole

Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:

Mole of CuSO4 = 0.23 mole

Volume of solution = 2 L

Molarity of CuSO4 =..?

Molarity = mole /Volume

Molarity of CuSO4 = 0.23 / 2

Molarity of CuSO4 = 0.115 M

Therefore, the molarity of the CuSO4 solution is 0.115 M.

5 0

4 years ago

1. A 250g chunk of metal is heated with 400 joules of energy and the temperature goes from 20 °C to 25°C. What is its specific h

Paha777 [63]

The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.

Given the following data:

Mass of metal = 250g

Quantity of energy = 400 Joules

Initial temperature = 20°C

Final temperature = 20°C

To determine the specific heat capacity of this chunk of metal:

<h3>The formula for quantity of heat.</h3>

Mathematically, quantity of heat is given by the formula;

$Q = mc\theta$

Where:

Q represents the quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity.

∅ represents the change in temperature.

Making c the subject of formula, we have:

$c = \frac{Q}{m\theta}$

Substituting the given parameters into the formula, we have;

$c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }$

Specific heat, c = 0.32 J/g°C.

Read more on specific heat here: brainly.com/question/2834175

5 0

2 years ago

A saturated solution of barium chloride at 30 degrees Celsius contains 150 g water. How much additional barium chloride can be d

Ksenya-84 [330]

Solubility of barium chloride at 30 degree Celsius is 38.2g /100 g water and solubility of barium chloride at 60 degree Celsius is 46.6 g / 100 g water.
The quantity of barium chloride that is dissolved in water at 30 degree Celsius = 38.2 * [150/100] = 57.30 g.
The quantity of barium chloride that will be dissolved in water at 60 degree Celsius = 46.6 * [150/100] = 69.90 g
The difference between these quantities is the amount of barium chloride that can be dissolved by heating the barium chloride to 60 degree Celsius.
69.90 - 57.30 = 12.60 g. Therefore, 12.60 g of barium chloride can still be dissolved in the water by heating the water to 60 degree Celsius.

8 0

3 years ago

Crossing a Dd parent with another Dd parent results in

MrRissso [65]

C).dd offspring have a nice day

3 0

3 years ago

Pick the correct statement for the following isotope: a. 42Ca 42 is the mass number and 20 is the atomic number. b. 42 is the nu

kramer

Answer:

Explanation:

To label an element correctly using a combination of the symbol, mass number and atomic number furnishes some important information about the element.

We can obtain these information from the element provided that correct labeling of the element is presented. Firstly, after writing the symbol of the element, the atomic number is placed as a subscript on the left while the mass number of the atomic mass is placed as a superscript on the same left.

Looking at the question asked, we have the element symbol in the correct position as Ca, with 42 also in the correct position which is the mass number. The third number which is 20 is thus the atomic number of the element.

4 0

3 years ago