Answer: Between 1 and 2.
Explanation:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
............(1)
where,
a = amount of reactant left after n-half lives = 40
= Initial amount of the reactant = 100
n = number of half lives
Putting in the values we get:
taking log on both sides
Thus half-lives that have elapsed is between 1 and 2
Answer:
Explanation:
Let us first take a look at the image below;
In the acid - base reaction; we can see the transfer of electrons that takes place;
We can also see that the reaction goes in the direction which converts the stronger acid and the stronger base to the weaker acid and the weaker base.
The stronger acid is shown with the one with more negative 
Value.
∴ The equilibrium constant for the acid-base reaction is expressed as:
From Value (shown in the image below), it is clear and vivid that hydrobromic acid is a stronger acid than the ethyloxonium ion, therefore the equilibrium lies to the right.
From the chemical equation (shown in the attached image); the equilibrium constant for the acid-base reaction can be expressed as:
Data can arranged into visual displays called graphs. There are multiple types of graphs such as bar graphs, line graphs, scatter plots, and pie charts.
hopefully this helps :)
Answer:
NH3(g) + H2O(1) → NH4+(aq) + OH (aq)
HF(aq) + H2O(1) → H3O+(aq) + F (aq)
Explanation:
Acid-base reactions are chemical reactions involving acids and bases. Acids tend to ionize/dissociate in water, a property which determines their strength. Ionization of an acid refers to the acid losing its hydrogen ion (H+) in water solution. An acid ionizes or dissociates to form a conjugate base.
A strong acid is so because it ionizes completely in water i.e. loses all its hydrogen ion (H+) while a weak acid partially ionizes in water.
In the chemical reactions;
1) NH3(g) + H2O(1) → NH4+(aq) + OH (aq)
H20 loses its hydrogen ion (H+) in this reaction to form an anion (OH-). Hence, water (H20) is an acid in this case which ionizes to form a conjugate base (OH-). This is an example of ionization of acid.
2) HF(aq) + H2O(1) → H3O+(aq) + F (aq)
Hydrogen fluoride (HF) loses its hydrogen ion (H+) in the presence of water to form anion (F-). The HF is the acid while F- is it's conjugate base. Thus, an example of ionization of acid
Unstable isotopes occur when the strong force is unable to overcome the <span> <span>electrostatic force.</span></span><span>
There are no stable isotopes in the elements at the upper end of the periodic table, which clearly demonstrates the limit of the ability of the nuclear binding energy or the residual strong force, to overcome the electrostatic repulsion of all those protons in the nucleus.
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