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notsponge [240]

3 years ago

5

Magnesium hydroxide is added to a solution of hydrochloric acid. A reaction occurs and magnesium chloride and water are formed.

Testing the _______ would show that a reaction has occurred.

1 answer:

kodGreya [7K]3 years ago

8 0

Answer:Magnesium (Mg) is a - reactant

Hydrogen (H2) is a - product

magnesium chloride (MgCI2) is a - product

hydrochloric acid (HCI) is a - reactant

Explanation: It’s in my notes

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Need help I don't remember what to do?

Lina20 [59]

I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
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10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!

4 0

3 years ago

The chemical formula for magnesium oxide is MgO. A chemist determined by measurements that 0.030 moles of magnesium oxide partic

tamaranim1 [39]

Answer:

1.209g of MgO participates

Explanation:

In this problem, we have 0.030 moles of MgO that participates in a particular reaction.

And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.

To convert moles to grams we need to use molar mass of the compound:

<em>1 atom of Mg has a molar mass of 24.3g/mol</em>

<em>1 atom of O has a molar mass of 16g/mol</em>

<em />

That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol

And mass of 0.030 moles of MgO is:

0.030 moles MgO * (40.3g/mol) =

<h3>1.209g of MgO participates</h3>

3 0

3 years ago

Ill give the brainliest answer to whoever helps me with this equation

vampirchik [111]

Answer: The percent yield for the $NaBr$ is, 86.7 %

Explanation : Given,

Moles of $FeBr_3$ = 2.36 mol

Moles of $NaBr$ = 6.14 mol

First we have to calculate the moles of $NaBr$

The balanced chemical equation is:

$2FeBr_3+3Na_2S\rightarrow Fe_2S_3+6NaBr$

From the reaction, we conclude that

As, 2 moles of $FeBr_3$ react to give 6 moles of $NaBr$

So, 2.36 moles of $FeBr_3$ react to give $\frac{6}{2}\times 2.36=7.08$ mole of $NaBr$

Now we have to calculate the percent yield for the $NaBr$ .

$\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield = 6.14 moles

Theoretical yield = 7.08 moles

Now put all the given values in this formula, we get:

$\text{Percent yield}=\frac{6.14mol}{7.08mol}\times 100=86.7\%$

Therefore, the percent yield for the $NaBr$ is, 86.7 %

6 0

3 years ago

Indicar la cantidad de sustancia en: a) 2.0L de un gas en C.N; b) 22.4 mL de un gas a 755 torr y 26 grados celsius?

nekit [7.7K]

Answer:

El termopar B presenta un mayor grado de dispersión y también es más preciso. ... (c) La estimación para T = 175 ° C es probablemente la más cercana al valor real, porque el ... (cm3). Flujo de masa. Velocidad. (kg / min). Diferencia. Duplicar. (Di). Yo y yo. 2. 1 ... atm de gas. 2. 2. 2 f. 3. 2 f f. 30 14,7 lb 20 pulg. 4 14,7 lb 24 pulg 392 lb 7,00 10 lb pulg.

8 0

3 years ago

Calculate the wavelength of a photon of light having a frequency of 3.50 x 1015 Hz.

Aliun [14]

Answer:

Wavelength, $\lambda=8.57\times 10^{-8}\ m$

Explanation:

Given that,

Frequency, $f=3.5\times 10^{15}\ Hz$

We need to find the wavelength of a photon of light. The relation between frequency and wavelength is as follows :

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.5\times 10^{15}}\\\\\lambda=8.57\times 10^{-8}\ m$

So, the wavelength of the light is $8.57\times 10^{-8}\ m$ .

4 0

3 years ago