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notsponge [240]
3 years ago
5

Magnesium hydroxide is added to a solution of hydrochloric acid. A reaction occurs and magnesium chloride and water are formed.

Testing the _______ would show that a reaction has occurred.
Chemistry
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:Magnesium (Mg) is a - reactant

Hydrogen (H2) is a - product

magnesium chloride (MgCI2) is a - product

hydrochloric acid (HCI) is a - reactant

Explanation: It’s in my notes

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The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0
3 years ago
Calculate the hydrogen-ion concentration (H+] for the aqueous solution in which [OH-1 is 1 x 10-12 mol/L.
Artemon [7]

Answer:If we have [H+][OH-]= Kw = 1.0 x 10^-14

Then [H+]= Kw/ [OH-]= 1.0x 10^-14/ 1 x 10^-11 =1 x 10^-3 mol/L

And here is the solution - as you can see it is an acidic one :

pH = - log [H+]= - log 1 x 10^-3 = 3 < 7

Explanation:

7 0
3 years ago
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What did Rutherford's gold-foil experiment help him conclude?
Svetach [21]
C. mass is protons and neutrons. Both are in the nucleus
8 0
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Why did you have to remove co2 from your partially neutralized stomach acid before the titration?
shutvik [7]

Answer is: carbon dioxide (CO₂) can affect the end point of the titration.

Carbon dioxide, or carbon(IV) oxide, reacts with water and form carbonic acid, which can affect the end point of the titration, because more base is needed for neutralization of partially neutralized stomach acid.

Balanced chemical reaction of carbon dioxide and water: CO₂ + H₂O → H₂CO₃.

8 0
3 years ago
What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t
Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

<u>Step 1:</u> Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

<u>Step 2:</u> The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g)         ΔH°rxn = -6278 kJ

<u>Step 3:</u> Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

<u>Step 4:</u> Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

<u>Step 5:</u> Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0
3 years ago
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