Answer:
B: Horizontally to the left
Explanation:
Horizontal velocity is always constant throughout the entire trajectory of the rocket and acts in the horizontal direction in which the rocket was launched. This is because gravity only acts in the downwards vertical direction.
So in order words at peak height, horizontal velocity is in the horizontal direction in which the rocket was launched.
So if it was to the left, then direction is left but if right, then direction is right.
Looking at the options, the most appropriate will be:
Horizontally to the left
Answer: Option D: 5.5×10²Joules
Explanation:
Work done is the product of applied force and displacement of the object in the direction of force.
W = F.s = F s cosθ
It is given that the force applied is, F = 55 N
The displacement in the direction of force, s = 10 m
The angle between force and displacement, θ = 0°
Thus, work done on the object:
W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J
Hence, the correct option is D.
Uhhhh...you should have paid attention in class, just saying...
According to Newton (2nd law), Force = (mass) x (acceleration)
Substitute what we know : Force = (1,000 kg) x (3 m/s²)
Do the arithmetic: Force = 3,000 kg-m/s² = 3,000 newtons
