Based on Kepler's work, which best describes the orbit If a planet around the Sun?
1 answer:
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Answer:
Hope it will help you :)
Explanation:
Answer:
15.8640053791 s
392.780107582 m
29.5184032275 m/s
Explanation:
0 denotes initial
x denotes displacement
c denotes car
t denotes truck
r denotes rear
For the car
The displacement of the truck will be
From the above two equations we get
The time taken is 15.8640053791 s
The distance the car travels is 392.780107582 m
The velocity of the car is 29.5184032275 m/s
Answer:
B=1.04*10^{-4}T
Explanation:
An infinite wire produces a magnetic field that can be computed with the formula:
where m0 is the magnetic permeability of vacuum (4pi*10^{-7}Tm/A), I is the current of the wire (2.50A) and r is the perpendicular distance to the wire in which B is calculated (3cm=3*10^{-2}m). By replacing we obtain:
hope this helps!!
Answer:
Explanation:
In this problem we can use Bohr's atomic model, to deal with the electronic transition, so we can have transitions between two given states.
ΔE = -E₀
Lower state final state energy
Fundamental first excited state ΔE₁ = -2.4 - (-4.7) = 2.3 eV
Fundamental second excited state ΔE₂ = -1.0 - (-4.7) = 3.7 eV
Fundamental third excited state ΔE₃ = -0.3 - (-4.7) = 4.4 eV
As they indicate that there are no electrons in the excited states these are the only possible transitions.
When a wide range of light strikes, the frequencies of these energies are absorbed and observed as black bands (absence of radiation) in the spectrum.