The frequency of sound at the given temperature is 200.58 Hz.
<h3>Frequency of sound at the given temperature</h3>
The frequency of sound at the given temperature is calculated as follows;
v = fλ
f = v/λ
where;
- v is speed of sound at 20 ⁰C = 343 m/s
- λ is wavelength of the sound = 1.71 m
f = 343/1.71
f = 200.58 Hz
Thus, the frequency of sound at the given temperature is 200.58 Hz.
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Answer:4 and 5
Explanation:it you add 1+3 and 2+3 it is 4 and 5
Answer:
100 m / s^
F =ma from this divided F and ma by m to get acceleration
a = F / m
a = ?
F = 5 N
m = 50 g = 0. 0 5 kg ; if 1 kg = 1000g how much kg of 50 g by criss cross method we get 0.05 kg
so; 5N / 0. 05 kg = 5kg m / s^ / 0.05 kg
kg cancel by kg
the result is 100 m/ s^
Answer:
B=μ₀I/2r
Explanation:
Produced magnetic field due to an existing electric field through a coil or conductor can be explained by Biot-Savart Law. Formula for this law is:
dB=(μ₀I/4π.r²)dL
Here,
r=Radius of the loop
I and r are constants with respect to length L.
To convert linear displacement L into angular displacement Ф:
dL=r.dФ
So,
dB=(μ₀I/4π.r²)r.dФ
dB=(μ₀I/4π.r)dФ
Integrating both sides over the circle i.e. from 0 radians to 2π radians (360⁰), while the integration will apply only on dФ as all others are constants.
B=(μ₀I/4πr)(2π-0)
<u>B=(μ₀I/2r)</u>
Responder:
50A
Explicación:
Dado que el Um chuveiro y el microondas están conectados en paralelo, el mismo voltaje fluirá a través de ellos.
La potencia total consumida por ambos aparatos = 4800W + 1200W
La potencia total consumida por ambos aparatos = 6000W
Para obtener el I actual, usaremos la fórmula;
P = IV
6000 = 120I
Yo = 6000/120
Yo = 50 A
Por lo tanto, la medición de corriente del amperímetro ideal A será 50A
