Which term is another name for fraunhofer diffraction?

Water drops from the nozzle of a shower onto the floor 81 inches below. The drops fall at regular intervals of time, the first d

Alexxx [7]

Answer:

0.91437 m

0.22859 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

$s=81\ inches=81\times 0.0254=2.0574\ m$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2.0574=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.0574\times 2}{9.81}}\\\Rightarrow t=0.64764\ s$

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

$t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.64764}{3}\\\Rightarrow t'=0.21588\ s$

For second drop time is given by

$t''=2t'\\\Rightarrow t''=2\times 0.21588\\\Rightarrow t''=0.43176\ s$

Distance from second drop

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.43176^2\\\Rightarrow s=0.91437\ m$

Distance from second drop is 0.91437 m

Distance from third drop

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.21588^2\\\Rightarrow s=0.22859\ m$

Distance from third drop is 0.22859 m

6 0

3 years ago

What is the energy due to compressing a spring

Westkost [7]

Answer: Elastic Potential Energy

Explanation: Energy present on compressed strings is called Elastic Potential Energy.

8 0

3 years ago

HELP!!!

FinnZ [79.3K]

A and B i think is the answer

7 0

3 years ago

Read 2 more answers

Contact lenses are designed to be gas permeable in order to allow oxygen to diffuse to the eye. If the edge of a contact lens is

guapka [62]

Answer: A

The diffusion time through the edge is double the diffusion time through the center.

Explanation:

Only the diffusion coefficient, thickness, surface area, distance affects the time it takes a gas such as oxygen to diffuse a given in a medium. The Diffusion time increases with the square of diffusion distance Also, the Increased surface area increases the rate of diffusion or the diffusion time, whereas a thicker membrane reduces the rate of diffusion or time it takes the gas to be permeable. Also, The greater the distance that a substance must travel, the slower the rate of diffusion The diffusion coefficient determines the time it takes a gas to diffuse. Also the Diffusion time is inversely proportional to the diffusion coefficient.

Now, If the edge of a contact lens is double the thickness of the central portion of the lens, then it will take more time for the gas to diffuse through the thicker portion. since its edge is double the central position, then the diffusion time will also be doubled. So Option A is the best answer-

The diffusion time through the edge is double the diffusion time through the center.

6 0

4 years ago

A boat initially traveling at 10. meters per second accelerates uniformly at the rate of 5.0 meters per second2 for 10. seconds.

guajiro [1.7K]

The initial speed of the boat is $v_0=10 m/s$
and its acceleration is $a=5.0 m/s^2$
Since the boat is moving by uniform accelerated motion, the distance covered by the boat in a time t=10 s is given by:
$S(t)=v_0 t + \frac{1}{2}at^2 = (10 m/s)(10 s)+ \frac{1}{2}(5m/s^2)(10s)^2 =350 m$
So, the boat covers a distance of 350 m in 10 seconds.

4 0

3 years ago