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aliina [53]
3 years ago
12

For the equilibrium reaction N2O4(g) ⇀↽ 2 NO2(g) taking place inside a sealed container fitted with a piston, predict the effect

of raising the piston (to increase the volume of the container) on the composition of the mixture. 1. The equilibrium will shift to favor formation of N2O4(g). 2. There will be no effect on the composition. 3. More information is needed. 4. The equilibrium will shift to favor formation of NO2(g).
Physics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

4. The equilibrium will shift to favor formation of NO2(g)

Explanation:

According to La Chatalier's Principle which states that when an equilibrium system undergoes changes either in temperature, volume or concentration; there will be in a change in the system in order to reach equilibrium.

From the above equation,

N2O4(g) ⇀↽ 2 NO2(g)

From the above reaction, there are 2 moles of gaseous product on the left and 1 mole of gaseous reactant.

Therefore, there are more moles of gases in the left hand side than the right hand side.

Because a decrease in volume favors the direction that produces fewer moles, an increase in volume will therefore shift this system towards the side with more moles of gases that is, more products are formed hence, this system will shift to right and produce more moles of products i.e more NO2(g) formed.

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A meteorite strikes the Moon at the speed of 11 km/s. It has KE of 60,500,000 J. What will be its mass?
Vikentia [17]
KE=1/2 mv²
60,500,000 = 1/2 m ( 11,000 m/s )²
60,500,000= 1/2 ( 11,000 )² m
60,500,000= 60,500,000 x m
m= 60,500,000/60,500,000
m= 1 kg
8 0
3 years ago
a pebble is dropped down a well and hits the water 1.5 seconds later. using the equations for motion with constant acceleration,
Effectus [21]
Let h = the distance from the edge of the wall to the water surface (m).

Use g = 9.8 m/s² and neglect air resistance.

The initial vertical velocity of the pebble is zero.
Because the pebble hits the surface of the water after 1.5 s, therefore
h = (1/2)*(9.8 m/s²)*(1.5 s)² = 11.025 m

Answer:  11.025 m
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What principle encourages us to resolve a set of stimuli such as trees across a ridgeline into smoothly flowing patterns
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Which of the following is an example of transmission of light? A. Light passes through a glass of water. B. A visor blocks sunli
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4 years ago
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What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a
astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section areaA = (2.00\times10^{-3})^2\ m

(I). We need to calculate the area of copper wire

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}

R=0.0742\ \Omega

(II). We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}

R=1.75\ \Omega

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0
4 years ago
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