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aliina [53]
3 years ago
12

For the equilibrium reaction N2O4(g) ⇀↽ 2 NO2(g) taking place inside a sealed container fitted with a piston, predict the effect

of raising the piston (to increase the volume of the container) on the composition of the mixture. 1. The equilibrium will shift to favor formation of N2O4(g). 2. There will be no effect on the composition. 3. More information is needed. 4. The equilibrium will shift to favor formation of NO2(g).
Physics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

4. The equilibrium will shift to favor formation of NO2(g)

Explanation:

According to La Chatalier's Principle which states that when an equilibrium system undergoes changes either in temperature, volume or concentration; there will be in a change in the system in order to reach equilibrium.

From the above equation,

N2O4(g) ⇀↽ 2 NO2(g)

From the above reaction, there are 2 moles of gaseous product on the left and 1 mole of gaseous reactant.

Therefore, there are more moles of gases in the left hand side than the right hand side.

Because a decrease in volume favors the direction that produces fewer moles, an increase in volume will therefore shift this system towards the side with more moles of gases that is, more products are formed hence, this system will shift to right and produce more moles of products i.e more NO2(g) formed.

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Hey, guys I kinda need help with this question, 1. The number of atoms of each element are not equal on both sides of the equati
Xelga [282]

Answer:

The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.

Explanation:

I hope thats what u needed.

5 0
3 years ago
Read 2 more answers
A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on
Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia, I=mr^2

Since, \omega=\dfrac{v}{r}

K_i=mv^2

K_i=96\times (0.24)^2=5.529\ J

Finally it stops, so the final energy of the hoop will be, K_f=0

The work done by the hoop is equal to the change in kinetic energy as :

W=K_f-K_i

W = -5.529 Joules

So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.

4 0
3 years ago
Reggie accidentally left his books on top of his car before he left for class. The books stayed on top of his car while he was d
Volgvan

Answer: When Reggie's car turned eastward, his books continued moving northward, causing them to slide off the top of his car. :)

8 0
3 years ago
In an emergency, a driver brings a car to a full stop in 5.0s. The car is traveling at a rate of 38m/s when the breaking begins.
Lana71 [14]

(a) By definition of average acceleration,

<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (0 - 38 m/s) / (5.0 s)

<em>a</em> = -7.6 m/s²

(b) Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>x</em> is the change in position. So

0² - (38 m/s)² = 2 (-7.6 m/s²) ∆<em>x</em>

∆<em>x</em> = 95 m

6 0
4 years ago
Pick the right statement about normal force: (section 5.7)
Montano1993 [528]

Answer:

A. Normal force is always perpendicular to the area of contact between an object and support.

Explanation:

Normal force is defined as the contact force. If there is no contact between the surfaces, they cannot applies a force which is normal on each other. For e.g, the surfaces of a cubical box and the cart cannot applies a force of normal on each other because of no contact.

If, when there is a contact between two surfaces they applies a normal force on each other, and this force is  perpendicular to the each other . This normal force is necessary to prevent object to penetrating into other.

7 0
3 years ago
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