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3 years ago

If the endpoints of the diameter of a circle are (−8, 0) and (−12, 2), what is the standard form equation of the circle?

Mathematics

2 answers:

Paladinen [302]3 years ago

8 0

A(-8,0) B(-12,12)the center is w((-8-12)/2 , (0+12)/2)....(midel [ AB]w(-10 ,6)the ridus is : r = AB/2AB = √(-12+8)²+(12-0)² = √16+144 =√160/2an equation in standard form equation of the circle :(x+10)²+(y-6)² = (√160/2)²=160/4 = 40

madreJ [45]3 years ago

7 0

The midpoint of a diameter is the centre of the circle.

The centre is important for finding the equation.

Midpoint = (-10, 1)

The radius is also important

I will include it in the image

Equation of circle (x +10)^2 + (y -2)^2 = 5

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The range is the ouutput from inputing the input
basically
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the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
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factor
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set to zero
k+6=0
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facor
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set to zer
k-7=0
k=7
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so the domain has the numbers
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it seems we only want the positive square roots so
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3 years ago

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Answer:

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Step-by-step explanation:

Given:

The base of a triangular prism has an area of 18 square inches .

And the height is 4.5 inches.

Now, to get the triangular prism volume.

The base area = 18 square inches.

Height = 4.5 inches.

Now, to get the volume of prism we put formula:

$Volume=\frac{1}{2} \times base\ area\times height\\\\Volume=\frac{1}{2} \times 18\times 4.5\\\\Volume=40.5\ cubic\ inches.$

Therefore, the volume for the triangular prism is 40.5 cubic inches.

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