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Shtirlitz [24]
4 years ago
14

How is hydroelectric power created?

Physics
1 answer:
Marizza181 [45]4 years ago
3 0
Your answer would be B because it's anything pushing water to create electricity so anything uses flowing water.
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A jewellery shop owner has two identical clear gemstones but cannot remember which one is diamond and which one is rutile. Rutil
pantera1 [17]

We know

\boxed{\sf n_{21}=\dfrac{C}{V}}

How he find:-

The owner will measure speed of light through the index(Diamond or rutile).Then using calculations he fill find which is the velocity of diamond or rutile

<h3> For diamond</h3>

\\ \sf\longmapsto n_D=\dfrac{C}{V_D}

\\ \sf\longmapsto 2.4=\dfrac{3\times 10^8ms^{-1}}{V_D}

\\ \sf\longmapsto V_D=\dfrac{3\times 10^8ms^{-1}}{2.4}

\\ \sf\longmapsto V_D=1.25\times 10^8ms^{-1}

\\ \sf\longmapsto V_D=125\times 10^6ms^{-1}

<h3>For rutile</h3>

\\ \sf\longmapsto n_R=\dfrac{C}{V_R}

\\ \sf\longmapsto V_R=\dfrac{C}{n_R}

\\ \sf\longmapsto V_R=\dfrac{3\times 10^8ms^{-1}}{2.9}

\\ \sf\longmapsto V_R=1.03\times 10^8

\\ \sf\longmapsto V_R=103\times 10^6ms^{-1}

5 0
3 years ago
A small object with mass 1.30 kg is mounted on one end of arod
Julli [10]

Answer:

(a) I_{system} = 1.014\ kg.m^{2}

(b) \tau = 0.0179\ N-m

Solution:

As per the question:

Mass of the object, m = 1.30 kg

Length of the rod, L = 0.780 m

Angular speed, \omega = 5010\ rev/min

Now,

(a) To calculate the rotational inertia of the system about the axis of rotation:

Since, the rod is mass less, the moment of inertia of the rotating system and that of the object about the rotation axis will be equal:

I_{system} = ML^{2} = 1.30\times (0.780)^{2} = 0.791\ kg.m^{2}

(b) To calculate the applied torque required for the system to rotate at constant speed:

Drag Force, F = 2.30\times 10^{- 2}\ N

\tau = FLsin\theta 90 = 2.30\times 10^{- 2}\times 0.780\times 1 = 0.0179\ N-m

3 0
3 years ago
Which of the following is considered a natural magnetic field on earth?
Nadusha1986 [10]

Im not really sure about my answer but im giving you a clue about magnetic fields..

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

_Askmeanything2♡

4 0
3 years ago
A car takes 10 minutes to travel 10 km calculate average speed of car.​
lisabon 2012 [21]

Answer:

(km/mins) × ( mins/hr) = km/hr

(10/10)×(60/1) =600/10 = 60 km /hr

......

5 0
3 years ago
The electric field between two parallel plates is uniform, with magnitude 646 N/C. A proton is held stationary at the positive p
Ahat [919]

Answer:

The distance from the positive plate at which the two pass each other is 0.0023 cm.

Explanation:

We need to find the acceleration of each particle first. Let's use the electric force equation.

F=Eq

ma=Eq

<u>For the proton</u>

m_{p}a_{p}=Eq_{p}

a_{p}=\frac{Eq_{p}}{m_{p}}

a_{p}=\frac{646*1.6*10^{-19}}{1.67*10^{−27}}

a_{p}=6.19*10^{10}\: m/s^{2}

<u>For the electron</u>

m_{e}a_{e}=Eq_{e}

a_{e}=\frac{Eq_{e}}{m_{e}}

a_{e}=\frac{646*1.6*10^{-19}}{9.1*10^{−31}}  

a_{e}=1.14*10^{14}\: m/s^{2}

Now we know that the plate separation is 4.26 cm or 0.0426 m. The travel distance of the proton plus the travel distance of the electron is 0.0426 m.

x_{p}+x_{e}=0.0426

Both of them have an initial speed equal to zero. So we have:

\frac{1}{2}a_{p}t^{2}+\frac{1}{2}a_{e}t^{2}=0.0426

t^{2}(a_{p}+a_{e})=2*0.0426

t^{2}=\frac{2*0.0426}{a_{p}+a_{e}}

t=\sqrt{\frac{2*0.0426}{6.19*10^{10}+1.14*10^{14}}}

t=2.73*10^{-8}\: s    

With this time we can find the distance from the positive plate (x(p)).

x_{p}=\frac{1}{2}a_{p}t^{2}

x_{p}=\frac{1}{2}6.19*10^{10}*(2.73*10^{-8})^{2}

x_{p}=0.0023\: cm

Therefore, the distance from the positive plate at which the two pass each other is 0.0023 cm.

I hope it helps you!

7 0
3 years ago
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