Answer:
-1m/s
Explanation:
We can calculate the speed of block A after collision
According to collision theory:
MaVa+MbVb = MaVa+MbVb (after collision)
Substitute the given values
5(3)+10(0) = 5Va+10(2)
15+0 = 5Va + 20
5Va = 15-20
5Va = -5
Va = -5/5
Va = -1m/s
Hence the velocity of ball A after collision is -1m/s
Note that the velocity of block B is zero before collision since it is stationary
The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
To find the answer, we need to know about the thermodynamic processes.
<h3>How to find the final temperature of the gas?</h3>
- Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
- In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
- The membrane is raptured without applying any external force, thus, dW=0.
- We have the first law of thermodynamic expression as,

,

- Thus, the final temperature of the system will be equal to the initial temperature,

<h3>How much work is done?</h3>
- We found that the process is isothermal,
- Thus, the work done will be,

Where, R is the universal gas constant.
<h3>What is a reversible process?</h3>
- Any process which can be made to proceed in the reverse direction is called reversible process.
- During which, the system passes through exactly the same states as in the direct process.
Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
Learn more about thermodynamic processes here:
brainly.com/question/28067625
#SPJ1
Answer:
the ans is D... good luck
Answer:
Amoebas have projections called pseudopods
Explanation:
Pseudopodia is the locomatary organ of amoeba. It helps them in movement and transportation.
Answer:

Explanation:
= Activation energy = 160 kJ
T = Temperature = 510 K
R = Universal gas constant = 8.314 J/mol K
The fraction of energy is given by

The fraction of energy is 