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Drupady [299]
3 years ago
8

Solve the system of equations. y= 3x y= x2-10

Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

(-5, 2) and (2, 6)

Step-by-step explanation:

Use the substitution method. We know that y = 3x and y = x^2 - 10, so we can set them equal to one another.

3x = x^2 - 10

x^2 - 3x - 10 = 0

Use the quadratic equation to solve for x.

x = - 5, 2

Now solve for y using these two values of x by substituting it back into the equations.

y = - 15,  6

In coordinate form, (-5, 2) and (2, 6)

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How do I answer this?
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Step-by-step explanation:

GCF of 10k^{3} ,6k^{3}

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What is the solution to the system of equations? Use any method. {y=−3x+1 {2x+5y=18
Softa [21]

Answer:

So the solution set of the equations are {(-1,4)}

or

the solution is x = -1 and y = 4

Step-by-step explanation:

Equations given to us are

y = -3x + 1                                ..................(i)

2x + 5y = 18                             .................(ii)

To find the value of x and y or the solution set of the system of equations

Now in first equation we see that

y = -3x + 1

Putting this value in equation (ii)

which is

2x + 5y = 18

Putting value of y from (i) in it

2x + 5(-3x + 1) = 18

Opening the bracket and multiplying inside

2x -15x + 5 = 18

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Subtracting 5 from both sides of the equation

-13x + 5 - 5 = 18 -5

-13x = 13

Dividing both sides by -13

\frac{-13x}{-13}=\frac{13}{-13}

Cutting out the same values gives us

x = -1

For value of y

putting value of x in equation (i)

which is

y = -3x + 1

Putting the value

y = -3(-1)+1

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So the solution set of the equations are {(-1,4)}

or

the solution is x = -1 and y = 4

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3 years ago
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