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Lapatulllka [165]
3 years ago
12

Mrs. Vanwhy made a two-way table to show which students made honor roll and which students study a foreign language.

Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer:

Its the 2nd table.

aksik [14]3 years ago
3 0

Answer:

2

Step-by-step explanation:

did it on edge

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22.45 would be 22, and 90.32 would be 90
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Simplify: 2⁶X5⁴X3¹²/2²x5²x3⁴​
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Step-by-step explanation:

2⁶X5⁴X3¹²/2²x5²x3⁴

2⁴ × 5²×3⁸

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
The diagonals of rhombus fghj intersect at point k. if side gh is equal to 3x - 10 and side jh is equal to 6x - 19, find x
exis [7]
A rhombus is a square but turned so it looks like a diamond. This means all the sides are equal. With this information we can build an equation to solve for x.

3x - 10 = 6x - 19

1) Subtract 3x from both sides.

-10 = 3x - 19

2) Add 19 to both sides.

9 = 3x

3) Divide both sides by 3.

3 = x

x =3.
8 0
3 years ago
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