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CaHeK987 [17]
2 years ago
9

Find the common ratio of the geometric sequence 4, -20, 100, -500, ...

Mathematics
1 answer:
asambeis [7]2 years ago
6 0

Answer:

r = -5. Find the pattern and write the recursive formula: a_n + 1 = - 5 a_nGiven the recursive formula: r =

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Yep here we go again:
Alchen [17]

Answer:

126

Step-by-step explanation:

360 x 35%= 126

360 x 0.35 = 126

3 0
2 years ago
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Find the distance between the points (-4, -5 and (3, -1.
Komok [63]
<u><em>≡ We know that:</em></u>
⇔ (x_{1},y_{1}) → (-4,-5)
⇔ (x_{2},y_{2}) → (3,-1)

<u><em>≡ Solution:</em></u>
⇒ \sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}
⇒ \sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}
⇒ \sqrt{[7^{2}+4^{2}]}
⇒ \sqrt{[49+16]}
⇒ \boxed{\sqrt{65}}
7 0
3 years ago
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For ΔABC, ∠A = 3x, ∠B = 2x - 3, and ∠C = x + 3. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' =
Mashutka [201]
I am not 100% sure but I think the answer is C I hope I helped you and Good luck
3 0
3 years ago
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How do you solve this 5b-28&gt;27
damaskus [11]
B>11 hope this helps :)

8 0
2 years ago
A husband and wife have normal vision, although both of the couple's fathers are red–green color-blind, an inherited X-linked re
Mekhanik [1.2K]

Answer:

1/2

Step-by-step explanation:

Since the recessive gene is carried in the x chromosome and a father can only pass it to a daughter, the father doesn't have the disease nor carries it.

The mother carries the recessive gene because her father passed her his conditioned gene (only having one x chromosome), while her mother gave her a normal one so she can have normal vision.  

The chance of having a boy or a girl is 1/2 and the chance of this baby of having both recessive gene is null because in order to have a girl that is color blind both her x chromosomes must have the recessive gene, but the father can't pass it since he doesn't carries it. Therefore the combined probability is 1/2*(1-0) = 1/2.

7 0
3 years ago
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