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AlekseyPX
3 years ago
5

What is the denominator of the simplified expression?(2n/6n+4)(3n+2/3n-2)

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0

Answer:

The denominator of the simplified expression is 3 n - 2

Step-by-step explanation:

Given expression as :

(\dfrac{\textrm 2n}{\textrm 6n+4} ) × (\dfrac{\textrm 3 n + 2}{\textrm 3 n - 2} )

or, \dfrac{\textrm 6n^{2}+4n }{\textrm 18n^{2}-12 n +12 n -8 }

Or, \dfrac{\textrm 6n^{2} + 4n }{18n^{2}-8 }

or,  \dfrac{\textrm 3n^{2} + 2n }{9n^{2}-4 }

Or, \dfrac{3n^{2}+2n }{(3n+2)(3n-2)}

Or,  \dfrac{n (3n + 2) }{(3n+2)(3n-2)}

∴ \dfrac{n}{3 n - 2}

Hence The denominator of the simplified expression is 3 n - 2  Answer

Anon25 [30]3 years ago
7 0

Answer: The correct answer is 3n-2

Step-by-step explanation:

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Solution given:

f(x)=x²

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(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25

24:

(gof)(x)=g(f(x))=g(x²)=x²+5

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(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36

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(hof)(x)=h(f(x))=h(x²)=4x²-6

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(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1

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