Question 20 is 2/11 i believe
To determine the number of possible arrangements for 6 out of 8, we should use combinations. That is
ₐC₆ = 8!/(6!2!)
Answer: b. Combination
Answer:
8 < x < 22
Step-by-step explanation:
If x is the third side , then
difference of 2 sides < x < sum of 2 sides , that is
15 - 7 < x < 15 + 7
8 < x < 22
Answer: Max is a very intelligent boy.
