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Alina [70]
3 years ago
10

A 45-year-old client diagnosed with colon cancer states, "I do not want any treatment. I have not seen any family members in 25

years. I am a loner. Besides, I will decide when and how I want to die." In which order of priority from first to last should the nurse perform the actions?
Mathematics
2 answers:
Kruka [31]3 years ago
7 0

Answer:

3,2,1,4

Step-by-step explanation:

I am a loner, I have not seen any of my family in 25 years, beside, i will decide when and how i want to die. I do not want any treatment.

Orlov [11]3 years ago
3 0

Answer: how and when

Step-by-step explanation:

The man will ask the nurse the different procedure available and then the nurse will request him to pick the procedure He would prefer.

The nurse will also ask him when he would like it to be performed and if he has any final request

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P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

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