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Alina [70]
3 years ago
10

A 45-year-old client diagnosed with colon cancer states, "I do not want any treatment. I have not seen any family members in 25

years. I am a loner. Besides, I will decide when and how I want to die." In which order of priority from first to last should the nurse perform the actions?
Mathematics
2 answers:
Kruka [31]3 years ago
7 0

Answer:

3,2,1,4

Step-by-step explanation:

I am a loner, I have not seen any of my family in 25 years, beside, i will decide when and how i want to die. I do not want any treatment.

Orlov [11]3 years ago
3 0

Answer: how and when

Step-by-step explanation:

The man will ask the nurse the different procedure available and then the nurse will request him to pick the procedure He would prefer.

The nurse will also ask him when he would like it to be performed and if he has any final request

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PLEASE HELP! I've posted the picture :)
Fiesta28 [93]
Umm use this apps ;) use me as the app jk
5 0
3 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
What is 5.4e+6 in numbers?
astraxan [27]

Answer:

5,400,000

Step-by-step explanation:

E+ simply means "to the power of" So your question is 5.4*10^6 which would turn out as 5,400,000

<u><em>Hope this helps!!!</em></u>

<u><em>Brady</em></u>

6 0
3 years ago
Can you help meee get this ?
nikdorinn [45]

Answer: y=4/5x-2 or y=4/5x+(-2)

Step-by-step explanation:

The formula for slope-intercept form is y=mx+b.

To find the slope, we can use the formula m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } and plugging in the points given.

m=\frac{6-2}{10-5} =\frac{4}{5}

We know our slope is 4/5. We can plug this into our slope-intercept form and then plug in a point to find b, y-intercept.

y=\frac{4}{5} x+b

2=\frac{4}{5}(5)+b

2=4+b

b=-2

We know the y-intercept is -2.

THe final equation is y=4/5x-2 or y=4/5x+(-2).

4 0
3 years ago
The vertex of the parabola below is at the point (1,-3). Which of the equations
kramer

Answer:

A

Step-by-step explanation:

A. X=-3(4-1)

3 0
3 years ago
Read 2 more answers
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