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sattari [20]
3 years ago
5

Describe the circle given by the equation (x − 7)^2 + (y − 8)^2 = 9.

Mathematics
1 answer:
matrenka [14]3 years ago
8 0
<h2>The circle (x − 7)² + (y − 8)² = 9 is a circle with center (7,8) and radius is 3</h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

          (x-h)²+(y-k)² = r²

Here we need to describe the circle given by the equation (x − 7)² + (y − 8)² = 9

Changing equation to  (x-h)²+(y-k)² = r² form

               (x − 7)² + (y − 8)² = 9

                (x − 7)² + (y − 8)² = 3²

So, h = 7 ,  k = 8 and r = 3

Center is (7,8) and radius is 3

The circle (x − 7)² + (y − 8)² = 9 is a circle with center (7,8) and radius is 3

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What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
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\star \blue{ \frak{To \: find :}}

\\  \\

  • value of x

\\  \\

\star \blue{ \frak{solution:}}

\\  \\

So to find value of x , we have to apply Linear Pair.

\\  \\

<u>Equation formed:</u>

\\  \\

\bigstar \boxed{ \tt(10x - 20) \degree + (6x + 8)\degree = 180 \degree}  \\

\\  \\

<u>Step by step expansion:</u>

\\  \\

\dashrightarrow  \sf(10x - 20) \degree + (6x + 8)\degree = 180 \degree \\

\\  \\

\dashrightarrow  \sf10x - 20 \degree + 6x + 8\degree = 180 \degree \\

\\  \\

\dashrightarrow  \sf10x +6x- 20 \degree  + 8\degree = 180 \degree \\

\\  \\

\dashrightarrow  \sf16x- 20 \degree  + 8\degree = 180 \degree \\

\\  \\

\dashrightarrow  \sf16x- 12\degree = 180 \degree \\

\\  \\

\dashrightarrow  \sf16x = 180 \degree + 12\degree\\

\\  \\

\dashrightarrow  \sf16x =192\degree\\

\\  \\

\dashrightarrow  \sf \: x = \frac{192\degree}{16\degree} \\

\\  \\

\dashrightarrow  \sf \: x = 12  \degree

\\  \\

\therefore \underline {\textsf{\textbf{Value of x is \red{12\degree}}}}

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