Answer:
B- Sodium loses an electron.
D- Fluorine gains an electron.
Sodium is oxidized.
Explanation:
The reaction equation is given as:
Na + F → NaF
In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.
Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.
This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.
Bob adds heat to a liquid substance. When enough heat is added, the liquid would undergo a phase transition from the liquid to the vapor phase. This process is called evaporation. It is an endothermic process where heat should be supplied to the system for the process to happen. The temperature of the system, when enough heat is supplied to allow phase transition, is called the boiling point. It is the temperature when the substance starts to boil in turn to a gas or a vapor. The heat that is associated during boiling is called the latent heat of vaporization. It is the heat that is absorbed during the phase change without changing the temperature of the system.
The specific heat of the metal is 2.4733 J/g°C.
Given the following data:
- Initial temperature of water = 25.0°C
- Final temperature of water = 29.0°C
- Temperature of metal = 203.0°C
We know that the specific heat capacity of water is 4.184 J/g°C.
To find the specific heat of the metal (J/g°C):
Heat lost by metal = Heat gained by water.
Mathematically, heat capacity or quantity of heat is given by the formula;
<u>Where:</u>
- Q is the heat capacity or quantity of heat.
- m is the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Substituting the values into the formula, we have:
Specific heat capacity of metal, c = 2.4733 J/g°C
Therefore, the specific heat of the metal is 2.4733 J/g°C.
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