Answer:
C
Explanation:
I got this question right on my test.
Answer : The specific heat of metal is 
.
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water = 
= mass of metal = 129.00 g
= mass of water = 45.00 g
= final temperature = 
= initial temperature of metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get
Therefore, the specific heat of metal is .
Answer:
Ea= -175.45J
A= 3.5×10^14
k=3.64 ×10^14 s^2.
Explanation:
From
ln k= -(Ea/R) (1/T) + ln A
This is similar to the equation of a straight line:
y= mx + c
Where m= -(Ea/R)
c= ln A
y= ln k
a)
Therefore
21.10 3 104= -(Ea/8.314)
Ea=-( 21.10 3 104×8.314)
Ea= -175.45J
b) ln A= 33.5
A= e^33.5
A= 3.5×10^14
c)
k= Ae^-Ea/RT
k= 3.5×10^14 × e^ -(-175.45/8.314×531)
k = 3.64 ×10^14 s^2.
Explanation:
It happens because particles of gas are in constant random motion. Thus they can collide with the walls of the container causing pressure on the walls.
Answer:
c. precipitation
Explanation:
Let's consider the following balanced net ionic equation.
Cl⁻(aq) + AgNO₃(ag) ⇒ AgCl(s) + NO₃⁻ (ag)
What kind of reaction is this?
a. acid-base. No, because the reactants are not acids and bases.
b. redox. No, because all the species have the same oxidation numbers in the reactants and the products
c. precipitation. Yes, because an insoluble compound (AgCl) is produced, which then precipitates.
