All categories

4 years ago

Which line from the prologue of Romeo and Juliet reveals the ending of the play?

Physics

2 answers:

KonstantinChe [14]4 years ago

7 0

Answer:

" A pair of star crossed lovers who take their life,

Whose misadventured piteous overthrows

Doth with their death bury their parents' strife"

Explanation:

The prologue is essential for the play for the following reasons:

-Sets the play in Verona

-Exposes Montagues and Capulates' rivalry

-Romeo and Juliet (the pair of star crossed lovers who take their life), come from these families.

ira [324]4 years ago

6 0

A pair of star-cross'd lovers take their life

You might be interested in

Which two of the following involve the same energy transfer. Assume that the same substance and the same mass is involved in all

Elanso [62]

B. evaporation
c. condensation

They are opposite processes that involve the same transfer of energy

3 0

3 years ago

What are the constituent metals of stainless steel?

bogdanovich [222]

<span>Stainless steel is a metal alloy that made up mainly of carbon and chromium. In combination with low carbon contents, chromium is highly reactive element that imparts remarkable resistance to corrosion and heat.</span>

Moreover, stainless steel is mixed up with sufficient nickel, which is an essential allying element in the series of stainless steel grades. Other components are manganese, molybdenum, silicon, titanium, aluminum, niobium, copper, nitrogen, and sulfur.

6 0

3 years ago

Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.

Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

We can solve this first part of the problem by applying the mirror equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

$f=\frac{R}{2}$

For this mirror, R = 20 cm, so its focal length is

$f=\frac{20}{2}=+10 cm$ (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm$

We can solve this part by using the magnification equation:

$M=-\frac{y'}{y}=\frac{q}{p}$

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

$y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm$

and the negative sign means that the image is inverted.

#LearnwithBrainly

6 0

3 years ago

Why doesn't the skateboarder roll as high each time she goes up the ramp

Westkost [7]

Answer:

The skater has mechanical/gravitational potential energy at the two meter mark. The skater gets to two meters high on the other end of the ramp. In terms of the conservation of energy, the skater will never go higher than two meter on the other end of the the ramp because energy can be neither created nor destroyed.

Explanation:

I hoping it is right!!!∪∧∪ ∪ω∪

6 0

3 years ago

Read 2 more answers

Help please

pychu [463]

The answer should be speed hope this helps

3 0

3 years ago

Read 2 more answers