Question

A ball rolls with a speed of 3 m/s across a level table that is 1.5m above the floor. How far along the floor is the landing spot from the table?

Answer 1

Answer:

d = 1.65 m

Explanation:

Given that,

The speed of a ball, v = 3 m/s

A ball rolls a level table that is 1.5 m above the floor.

We can find how long the ball is in free fall. We can use the second equation of kinematics as follows :

$s=ut+\dfrac{1}{2}gt^2$

u is the initial speed in the vertical direction

So,

$s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 1.5}{9.8}} \\\\t=0.55\ s$

Now, using the formula of velocity.

$v=\dfrac{d}{t}\\\\d=vt\\\\d=3\times 0.55\\\\d=1.65\ m$

So, the landing spot is at 1.65 m from the table.